Alcohols are really bad leaving groups, so we're often in the position where we want to convert the alcohol to a better leaving group. And one of the options that we can use is sulfonate esters. It turns out that sulfonate esters are really the ultimate leaving groups of organic chemistry because they're so extremely stable after they leave. They do an amazing job balancing out that negative charge and delocalizing it. So, how do we turn an alcohol into a sulfonate ester? All we do is we just use the chloride of that sulfonate ester. So we're going to use a sulfonyl chloride to convert the alcohol into a sulfonate ester. And I'll show you guys how to do that in just a second.
First of all, what is a sulfonate ester? Well, if you guys remember, the general structure was just that you had basically an S with 2 double bond O's. S==O=O So I'm just going to draw a line here. And then you had an R group. So a sulfonate ester would have basically an O on this side, =O where the Cl is, then an S, the 2 double one O's and then your R group. Now the identity of the R group is just going to change the name of the sulfonate ester.
In general, all of these different molecules can be categorized as sulfony esters but they do get individual names. So, for example, the simplest situation would just be what if it's just a methyl group? Well, then that's called a mesyl or a mesylate sulfonate ester or mesylate. How about if it's a benzene ring with a methyl group? Well, then that's called a tosyl. So basically, if the R is a benzene and a CH3, then that's a tosylate. And finally, if it's a CF3, so I just replace 3 H's with F's, that's called a triflate.
What is a Sulfonyl Chloride? Well, a Sulfonyl Chloride just means remove the O and put a chlorine right there. SOCl Okay? So, let's just start off with the first step of the mechanism. When my oxygen on the alcohol is considered my nucleophile because it has electrons that are freely able to donate, it will initiate the reaction. If I were to attack one of the atoms on the Sulfonyl Chloride, the sulfur, due to electron pull, creates a partial positive, thus being the most electrophilic. I'm going to move these electrons up to the O, creating a structure with a new bond formation and cleavage that leads to a stable intermediate. Now the next step might involve dealing with the good leaving group, Cl. I could just reform the double bond and kick out the Cl. This will transform the intermediate into a sulfonate ester.
Finally, this is how the sulfonate ester looks: O=S-=OR. Notice how stable this structure is due to no formal charges anymore. We can keep this sulfonate ester around as long as we want, just like an alkyl halide, and then when I finally want to react with it, I could introduce a nucleophile for a backside attack.
This reaction amazingly proceeds with retention of configuration because the oxygen never moves, maintaining its position throughout the reaction. This contrasts reactions with thionyl chloride and phosphorus bromide, which proceed with inversion of configuration during their nucleophilic substitution reactions.