Lapse rates in the atmosphere Refer to Example 2. Concurrent measurements indicate that at an elevation of 6.1 km, the temperature is -10.3° C and at an elevation of 3.2km , the temperature is 8.0°C . Based on the Mean Value Theorem, can you conclude that the lapse rate exceeds the threshold value of 7°C/ km at some intermediate elevation? Explain.
Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
4. Applications of Derivatives
Differentials
Struggling with Calculus?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
If , find the differential when and .
A
0.02
B
0.0025
C
2.00
D
0.025

1
First, identify the function given: \( f(x) = \sqrt{x + 2} \).
To find the differential \( dy \), we need to compute the derivative \( f'(x) \). Use the chain rule to differentiate \( f(x) = \sqrt{x + 2} \). The derivative is \( f'(x) = \frac{1}{2\sqrt{x + 2}} \).
Evaluate the derivative at \( x = 2 \). Substitute \( x = 2 \) into \( f'(x) \) to get \( f'(2) = \frac{1}{2\sqrt{2 + 2}} = \frac{1}{2\sqrt{4}} = \frac{1}{4} \).
The differential \( dy \) is given by \( dy = f'(x) \cdot dx \). Substitute \( f'(2) = \frac{1}{4} \) and \( dx = 0.01 \) into this formula to get \( dy = \frac{1}{4} \times 0.01 \).
Simplify the expression for \( dy \) to find the approximate change in \( y \) when \( x \) changes by \( dx = 0.01 \).
Watch next
Master Finding Differentials with a bite sized video explanation from Patrick
Start learningRelated Videos
Related Practice