Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
4. Applications of Derivatives
Differentials
Problem 113
Textbook Question
The circumference of the equator of a sphere is measured as 10 cm with a possible error of 0.4 cm. This measurement is used to calculate the radius. The radius is then used to calculate the surface area and volume of the sphere. Estimate the percentage errors in the calculated values of
a. the radius.
b. the surface area.
c. the volume.

1
To find the radius of the sphere, use the formula for the circumference of a circle: \( C = 2\pi r \). Solve for \( r \) to get \( r = \frac{C}{2\pi} \). Substitute the given circumference (10 cm) to find the radius.
Calculate the error in the radius using the formula for error propagation: \( \Delta r = \frac{\Delta C}{2\pi} \), where \( \Delta C = 0.4 \) cm is the error in the circumference.
Estimate the percentage error in the radius by dividing the error in the radius by the calculated radius and multiplying by 100: \( \text{Percentage error in } r = \left( \frac{\Delta r}{r} \right) \times 100 \).
For the surface area \( A \) of the sphere, use the formula \( A = 4\pi r^2 \). The error in the surface area can be estimated using \( \Delta A = 8\pi r \Delta r \). Calculate the percentage error in the surface area: \( \text{Percentage error in } A = \left( \frac{\Delta A}{A} \right) \times 100 \).
For the volume \( V \) of the sphere, use the formula \( V = \frac{4}{3}\pi r^3 \). The error in the volume can be estimated using \( \Delta V = 4\pi r^2 \Delta r \). Calculate the percentage error in the volume: \( \text{Percentage error in } V = \left( \frac{\Delta V}{V} \right) \times 100 \).

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Circumference and Radius Relationship
The circumference of a sphere is directly related to its radius through the formula C = 2πr, where C is the circumference and r is the radius. Understanding this relationship is crucial for calculating the radius from the given circumference measurement. Any error in the circumference will propagate to the radius calculation, affecting subsequent calculations.
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Propagation of Errors
Propagation of errors refers to how uncertainties in measurements affect the final results of calculations. When calculating derived quantities like surface area and volume from the radius, the percentage error in the radius will influence the percentage errors in these derived quantities. This concept is essential for estimating how measurement inaccuracies impact overall results.
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Surface Area and Volume Formulas
The surface area and volume of a sphere are calculated using the formulas A = 4πr² for surface area and V = (4/3)πr³ for volume. Understanding these formulas is necessary to compute the surface area and volume based on the radius. The relationship between the radius and these derived quantities highlights how changes in the radius affect the overall measurements.
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