Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
4. Applications of Derivatives
Differentials
Problem 12
Textbook Question
11–18. Rolle’s Theorem Determine whether Rolle’s Theorem applies to the following functions on the given interval. If so, find the point(s) guaranteed to exist by Rolle’s Theorem.
ƒ(x) = sin 2x; [0, π/2]

1
First, recall Rolle's Theorem, which states that if a function f is continuous on the closed interval [a, b], differentiable on the open interval (a, b), and f(a) = f(b), then there exists at least one c in (a, b) such that f'(c) = 0.
Check the function f(x) = sin(2x) for continuity on the interval [0, π/2]. Since sine is a continuous function and 2x is a linear transformation, f(x) is continuous on [0, π/2].
Verify that f(x) is differentiable on the open interval (0, π/2). The function sin(2x) is differentiable everywhere, so it is differentiable on (0, π/2).
Evaluate f at the endpoints of the interval: f(0) = sin(2*0) = sin(0) = 0 and f(π/2) = sin(2*(π/2)) = sin(π) = 0. Since f(0) = f(π/2), the condition f(a) = f(b) is satisfied.
Find the derivative f'(x) = d/dx [sin(2x)] = 2cos(2x). Set f'(x) = 0 to find the point(s) guaranteed by Rolle's Theorem: 2cos(2x) = 0. Solve for x in the interval (0, π/2) to find the value(s) of c where f'(c) = 0.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Rolle's Theorem
Rolle's Theorem states that if a function is continuous on a closed interval [a, b], differentiable on the open interval (a, b), and the function values at the endpoints are equal (f(a) = f(b)), then there exists at least one c in (a, b) such that f'(c) = 0. This theorem is essential for finding critical points where the function's slope is zero.
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Continuity and Differentiability
For Rolle's Theorem to apply, the function must be continuous on the closed interval and differentiable on the open interval. Continuity ensures there are no breaks or jumps in the function, while differentiability means the function has a defined derivative at every point in the interval, allowing for the application of the theorem.
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Finding Critical Points
Once it is established that Rolle's Theorem applies, the next step is to find the critical points where the derivative of the function equals zero. This involves calculating the derivative of the function and solving for x to find the point(s) c in the interval (a, b) where the slope of the tangent line is horizontal, indicating a local extremum.
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