Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
4. Applications of Derivatives
Differentials
Problem 4.6.59`
Textbook Question
Approximating changes
Approximate the change in the lateral surface area (excluding the area of the base) of a right circular cone of fixed height h = 6m when its radius decreases from r = 10 m to r = 9.9 m (S = πr√(r² + h²).

1
Identify the formula for the lateral surface area of a right circular cone, which is given by \( S = \pi r \sqrt{r^2 + h^2} \). Here, \( h = 6 \) meters is constant.
To approximate the change in the lateral surface area, use the concept of differentials. The differential \( dS \) can be expressed as \( dS = \frac{\partial S}{\partial r} \cdot dr \), where \( dr \) is the change in radius.
Calculate the partial derivative of \( S \) with respect to \( r \). This involves using the product rule and chain rule: \( \frac{\partial S}{\partial r} = \pi \sqrt{r^2 + h^2} + \pi r \cdot \frac{r}{\sqrt{r^2 + h^2}} \).
Simplify the expression for \( \frac{\partial S}{\partial r} \) to get \( \frac{\partial S}{\partial r} = \pi \left( \sqrt{r^2 + h^2} + \frac{r^2}{\sqrt{r^2 + h^2}} \right) \).
Substitute \( r = 10 \) m and \( dr = -0.1 \) m into the expression for \( dS \) to approximate the change in the lateral surface area: \( dS = \frac{\partial S}{\partial r} \bigg|_{r=10} \cdot (-0.1) \).

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Differential Calculus
Differential calculus focuses on the concept of the derivative, which measures how a function changes as its input changes. In this context, it helps us approximate the change in the lateral surface area of the cone as the radius changes slightly. By using derivatives, we can find the rate of change of the surface area with respect to the radius.
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Surface Area of a Cone
The lateral surface area of a right circular cone is given by the formula S = πr√(r² + h²), where r is the radius and h is the height. Understanding this formula is crucial for calculating the surface area before and after the change in radius. It highlights the relationship between the radius and the surface area, which is essential for applying calculus concepts.
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Linear Approximation
Linear approximation is a method used to estimate the value of a function near a given point using the tangent line at that point. In this problem, we can use the derivative of the surface area function to approximate the change in surface area when the radius decreases slightly from 10 m to 9.9 m. This technique simplifies complex calculations by providing a close estimate.
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