Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
4. Applications of Derivatives
Differentials
Problem 4.7.41
Textbook Question
17–83. Limits Evaluate the following limits. Use l’Hôpital’s Rule when it is convenient and applicable.
lim_x→∞ (e¹/ₓ - 1)/(1/x)

1
First, identify the form of the limit as x approaches infinity. Substitute x with infinity in the expression (e^(1/x) - 1)/(1/x) to see if it results in an indeterminate form like 0/0 or ∞/∞.
Notice that as x approaches infinity, 1/x approaches 0. Therefore, e^(1/x) approaches e^0, which is 1. This makes the numerator e^(1/x) - 1 approach 0, and the denominator 1/x also approaches 0, resulting in the indeterminate form 0/0.
Since the limit is in the indeterminate form 0/0, l'Hôpital's Rule can be applied. According to l'Hôpital's Rule, take the derivative of the numerator and the derivative of the denominator separately.
The derivative of the numerator e^(1/x) - 1 with respect to x is found using the chain rule. The derivative of e^(1/x) is e^(1/x) multiplied by the derivative of 1/x, which is -1/x². Therefore, the derivative of the numerator is -e^(1/x)/x².
The derivative of the denominator 1/x with respect to x is -1/x². Now, apply l'Hôpital's Rule by substituting these derivatives into the limit: lim_x→∞ (-e^(1/x)/x²)/(-1/x²). Simplify the expression and evaluate the limit as x approaches infinity.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Limits
Limits are fundamental concepts in calculus that describe the behavior of a function as its input approaches a certain value. They help in understanding the function's behavior at points where it may not be explicitly defined, such as at infinity or discontinuities. Evaluating limits is crucial for determining continuity, derivatives, and integrals.
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l'Hôpital's Rule
l'Hôpital's Rule is a method used to evaluate limits that result in indeterminate forms, such as 0/0 or ∞/∞. The rule states that if the limit of f(x)/g(x) leads to an indeterminate form, the limit can be found by taking the derivative of the numerator and the derivative of the denominator separately. This process can be repeated if the result remains indeterminate.
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Power Rules
Exponential Functions
Exponential functions, such as e^(1/x), are functions where a constant base is raised to a variable exponent. They exhibit unique properties, particularly as the variable approaches infinity or zero. Understanding the behavior of exponential functions is essential for evaluating limits involving them, especially in the context of growth rates and asymptotic behavior.
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