Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
4. Applications of Derivatives
Differentials
Problem 55b
Textbook Question
{Use of Tech} Approximating reciprocals To approximate the reciprocal of a number a without using division, we can apply Newton’s method to the function f(x) = 1/x - a.
b. Apply Newton’s method with a = 7 using a starting value of your choice. Compute an approximation with eight digits of accuracy. What number does Newton’s method approximate in this case?

1
Step 1: Understand the problem. We want to approximate the reciprocal of a number 'a' using Newton's method. The function we will use is f(x) = 1/x - a, where 'a' is the number whose reciprocal we want to find.
Step 2: Set up Newton's method. Newton's method is an iterative process given by the formula: x_{n+1} = x_n - f(x_n)/f'(x_n). We need to find the derivative of f(x) = 1/x - a.
Step 3: Calculate the derivative f'(x). The derivative of f(x) = 1/x - a is f'(x) = -1/x^2. This will be used in the Newton's method formula.
Step 4: Choose a starting value x_0. Since we are approximating the reciprocal of 7, a reasonable starting value might be x_0 = 0.1, as it is close to the reciprocal of 7.
Step 5: Apply Newton's method iteratively. Use the formula x_{n+1} = x_n - (1/x_n - 7)/(-1/x_n^2) to update x_n. Continue iterating until the approximation reaches eight digits of accuracy.

This video solution was recommended by our tutors as helpful for the problem above
Video duration:
6mPlay a video:
Was this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Newton's Method
Newton's Method is an iterative numerical technique used to find approximate solutions to equations. It starts with an initial guess and refines it using the formula x_{n+1} = x_n - f(x_n)/f'(x_n), where f is the function and f' is its derivative. This method is particularly useful for finding roots of functions, such as approximating reciprocals.
Recommended video:
Evaluating Composed Functions
Function and Derivative
In calculus, a function represents a relationship between inputs and outputs, while its derivative measures the rate of change of the function at any given point. For the function f(x) = 1/x - a, the derivative f'(x) = -1/x^2 is essential for applying Newton's Method, as it helps determine the slope of the tangent line at the current approximation.
Recommended video:
Derivatives of Other Trig Functions
Convergence and Accuracy
Convergence refers to the process by which an iterative method approaches a final value or solution. In the context of Newton's Method, achieving eight digits of accuracy means that the approximation is refined until the result is stable to that level of precision. Understanding how quickly and accurately the method converges is crucial for effectively using it to approximate values.
Recommended video:
Derivatives