Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
4. Applications of Derivatives
Differentials
Problem 54b
Textbook Question
Growth rate of bamboo Bamboo belongs to the grass family and is one of the fastest growing plants in the world.
b. Based on the Mean Value Theorem, what can you conclude about the instantaneous growth rate of bamboo measured in millimeters per second between 10:00 A.M. and 3:00 P.M.?

1
First, understand the Mean Value Theorem (MVT). It states that for a continuous function f on a closed interval [a, b], there exists at least one point c in the open interval (a, b) such that the derivative f'(c) is equal to the average rate of change of the function over [a, b].
Identify the function f(t) that represents the growth of bamboo over time, where t is the time in seconds. The interval [a, b] corresponds to the time from 10:00 A.M. to 3:00 P.M. Convert these times into seconds to find the interval.
Calculate the average growth rate of bamboo over the interval [a, b]. This is done by finding the difference in bamboo height at the end points of the interval and dividing by the total time elapsed. Use the formula: \( \frac{f(b) - f(a)}{b - a} \).
Apply the Mean Value Theorem. According to MVT, there exists a time c within the interval (a, b) where the instantaneous growth rate, represented by the derivative f'(c), is equal to the average growth rate calculated in the previous step.
Conclude that at some point between 10:00 A.M. and 3:00 P.M., the instantaneous growth rate of bamboo is equal to the average growth rate over that time period. This means that the bamboo grows at a rate that matches the average rate at least once during this interval.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Mean Value Theorem
The Mean Value Theorem (MVT) states that if a function is continuous on a closed interval and differentiable on the open interval, there exists at least one point where the instantaneous rate of change (derivative) equals the average rate of change over that interval. This theorem is crucial for understanding how a function behaves between two points and can be applied to determine specific growth rates.
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Instantaneous Growth Rate
The instantaneous growth rate refers to the rate at which a quantity changes at a specific moment in time, represented mathematically as the derivative of a function. In the context of bamboo growth, it indicates how fast the bamboo is growing at a particular time, which can be derived from the function modeling its growth over the specified time interval.
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Average Growth Rate
The average growth rate is calculated as the change in the quantity over a specified time period divided by the length of that time period. For bamboo growth between 10:00 A.M. and 3:00 P.M., this would involve measuring the total growth in millimeters during that time and dividing it by the number of seconds in that interval, providing a baseline for comparison with the instantaneous growth rate.
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