Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
4. Applications of Derivatives
Differentials
Problem 48
Textbook Question
Means
b. Show that the point guaranteed to exist by the Mean Value Theorem for f(x) = 1/x on [a,b], where 0 < a < b, is the geometric mean of a and b; that is, c = √ab.

1
First, recall the Mean Value Theorem (MVT) which states that if a function f(x) is continuous on the closed interval [a, b] and differentiable on the open interval (a, b), then there exists at least one point c in (a, b) such that f'(c) = (f(b) - f(a)) / (b - a).
Verify that f(x) = 1/x is continuous on [a, b] and differentiable on (a, b). Since 0 < a < b, f(x) is continuous and differentiable on these intervals.
Calculate f'(x) for f(x) = 1/x. The derivative f'(x) is given by f'(x) = -1/x^2.
Apply the MVT: Set f'(c) = (f(b) - f(a)) / (b - a). Substitute f(x) = 1/x to get -1/c^2 = (1/b - 1/a) / (b - a).
Solve the equation -1/c^2 = (1/b - 1/a) / (b - a) for c. Simplify the right-hand side and solve for c to show that c = √ab, the geometric mean of a and b.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Mean Value Theorem
The Mean Value Theorem (MVT) states that if a function is continuous on a closed interval [a, b] and differentiable on the open interval (a, b), then there exists at least one point c in (a, b) where the derivative of the function equals the average rate of change over that interval. This theorem is fundamental in understanding the behavior of functions and their derivatives.
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Geometric Mean
The geometric mean of two positive numbers a and b is defined as the square root of their product, expressed as √(ab). It is particularly useful in various mathematical contexts, including statistics and finance, as it provides a measure of central tendency that is less affected by extreme values compared to the arithmetic mean.
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Derivative
A derivative represents the rate at which a function changes at a given point and is a fundamental concept in calculus. It is defined as the limit of the average rate of change of the function as the interval approaches zero. Understanding derivatives is crucial for applying the Mean Value Theorem, as it helps identify the point where the instantaneous rate of change matches the average rate of change.
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Derivatives