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Ch.21 - Organic Chemistry

Chapter 21, Problem 83c

Name each ether. c.

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Welcome back, everyone. Write the name of the given Ether. Let's recall how we name Ether. So Ether generally have a form of R one bonded to oxygen that is bonded to R two. Those are are the LK groups, right? And essentially we name our Ether says LK one, I'll kill two, followed by Ether. We essentially want to arrange our Alky subscriptions alphabetically as well. So what we're going to do is essentially understand what sort of Alky substituents. We have bonded to oxygen. Looking at the left, we have 12345, a six member chain. So that's a heel substituent. And as a result, one of our alcal groups is heel, looking at the right hand side, we are going to think about the next Alky subit and that contains 12345, also six carbon atoms. So that's heel because the two substitutions are exactly the same. We're not going to say heel heel either, but we're just going to combine them into di heel, which tells us that there are two heel substi bonded to oxygen, right? So our name of this Ether would actually be Dixy Ether and that's our final answer. Thank you for watching.