Determine the products of each carboxylic acid reaction. b.

Video transcript

Welcome back, everyone draw the products of the reaction of the given carboxylic acid. We're given a di carboxylic acid, right? Because we have two carboxyl groups within the same molecule. And essentially there is only heat present in the reaction. And we have to understand that this is an intra molecular condensation reaction. In a condensation reaction. We have to recall that we are losing a molecule with a low molecular weight such as water. Specifically, we can notice that the two carboxyl groups, they have two hydroxyl groups, right? And these hydroxyl groups can be combined in such a way that we form water h2o or hoh. So one of our products in a condensation reaction could be HTO and it would be H2O in this case, because we have two hydroxyl groups. If we are combining hoh, we're only left with one oxygen that gets attached to the other carbel group, right? And essentially it replaces the whole oh, since we're losing it, so our next product would essentially be a five member drain formed. Let's go ahead and throw it out. We have carbons, 123 or an oxygen would be number five. So let's go ahead and throw the resultant five member ring. We can also draw the Carbel. Now, this carbel is now attached to oxygen, which is attached to another car bono. That's it. We have formed an anhydride, right? So we can essentially label our carbons just in case we have carbons for we to one, right? And basically we have created a five member ring. So those will be our products. Let's label them as our final answer. Thank you for watching.