21. Nuclear Chemistry

Calcium-41 is commonly used radioisotope in the study of osteoporosis. If calcium-41 has a mass of 40.962278 amu, determine the nuclear binding energy per nucleon in MeV. (1 amu = 1.66 x 10^-27 kg). (1 MeV = 1.60 x 10^-13 J)

Calculate the mass defect (in g/mol) for the formation of a helium-6 nucleus, and calculate the binding energy in (MeV)/nucleon. (1 amu = 1.66 x 10^-27 kg). (1 neutron = 1.00866 amu 1 proton = 1.00727 amu, & 1 electron = 0.00055 amu) (1 MeV = 1.60 x 10^-13 J).

How much energy must be supplied to break a single aluminum-27 nucleus into separated protons and neutrons if an aluminum-27 atom has a mass of 26.9815386 amu? How much energy is required for 100.0 g of aluminum-27? (The mass of an electron is given on the inside back cover.)

Based on the following atomic mass values: ¹H, 1.00782 amu; ²H, 2.01410 amu; ³H, 3.01605 amu; ³He, 3.01603 amu; ⁴He, 4.00260 amu—and the mass of the neutron given in the text, calculate the energy released per mole in each of the following nuclear reactions, all of which are possibilities for a controlled fusion process:

(a) ²₁H + ³₁H → 4₂He + ¹₀n

(b) ²₁H + ²₁H → ³₂He + ¹₀n

(c) ²₁H + ³₂He → ⁴₂He + ¹₁H

If 1.0 g of matter is converted to energy, how much energy is formed?