Skip to main content
Ch 24: Gauss' Law
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Not the one you use?Change textbook
Chapter 24, Problem 25a

A thin, horizontal, 10-cm-diameter copper plate is charged to 3.5 nC. If the charge is uniformly distributed on the surface, what are the strength and direction of the electric field 0.1 mm above the center of the top surface of the plate?

Verified step by step guidance
1
Determine the surface charge density (σ) of the copper plate. The surface charge density is given by the formula: σ=QA, where Q is the total charge (3.5 nC) and A is the area of the plate. The area of a circular plate is calculated as A=πr², with r being the radius of the plate (5 cm or 0.05 m).
Recognize that the plate is a thin, uniformly charged conductor. For a point very close to the surface of a conductor, the electric field strength is given by: E=σε, where ε is the permittivity of free space (ε=8.85×1012 C²/N·m²). Substitute the value of σ from step 1 into this formula to calculate the electric field strength.
Since the point of interest is 0.1 mm (0.0001 m) above the center of the top surface of the plate, the electric field will be perpendicular to the surface of the plate. For a uniformly charged flat conductor, the electric field direction is always normal (perpendicular) to the surface, pointing away from the surface if the charge is positive.
Verify that the distance above the plate (0.1 mm) is negligible compared to the plate's dimensions. This ensures that the approximation of the electric field as uniform and perpendicular to the surface is valid.
Combine the results from the previous steps to express the electric field strength and direction. The electric field strength is given by the formula derived in step 2, and the direction is perpendicular to the plate's surface, pointing upward since the charge is positive.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
6m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Electric Field

The electric field is a vector field that represents the force exerted by an electric charge on other charges in its vicinity. It is defined as the force per unit charge and is measured in newtons per coulomb (N/C). The direction of the electric field is away from positive charges and towards negative charges, indicating the direction a positive test charge would move.
Recommended video:
Guided course
03:16
Intro to Electric Fields

Surface Charge Density

Surface charge density is the amount of electric charge per unit area on a surface, typically denoted by the symbol σ (sigma). It is calculated by dividing the total charge by the area over which it is distributed. For a uniformly charged plate, this concept is crucial for determining the electric field above the surface, as it directly influences the field strength.
Recommended video:
Guided course
04:03
Surface Charge Density

Gauss's Law

Gauss's Law relates the electric field to the charge enclosed within a closed surface. It states that the electric flux through a closed surface is proportional to the enclosed charge. This principle is particularly useful for calculating electric fields in symmetric charge distributions, such as a uniformly charged plate, allowing for straightforward determination of the field strength at specific points.
Recommended video: