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Ch. 26 - Population and Evolutionary Genetics

Chapter 25, Problem 10

Consider a population in which the frequency of allele A is p=0.7 and the frequency of allele a is q=0.3 and where the alleles are codominant. What will be the allele frequencies after one generation if the following occurs?

wAA=1, wAa=0.95, waa=0.9

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Hi everyone. Let's take a look at this practice problem together determine the number of homosexuals dominant individuals in a population of 8000. If the frequency of the recessive allele is 0.5. Now recall that there is a formula that you need to know and that is the hardy Weinberg formula and what the hardy Weinberg formula lets us do is measure the frequencies of both alleles and gina types in a population. Now the formula is P squared plus two PQ plus Q squared equals one. Where P. Is the dominant little frequency and Q. Is the recess of a little frequency. Now let's take the lil and we're going to represent our recessive A lil with little A. Therefore our dominant allele would be capital A. So in the hardy Weinberg equation P two is the number of Homo zegas dominant individuals. Two P. Q. Is the number of heterocyclic individuals and Q squared is the number of Homo zegas recessive individuals. Another part of this equation is that the total number of the little frequency should be one. So what that means is that The dominant a little frequency plus the recessive. A little frequency equals one. Now we know that the recessive, a little frequency is 0.5. So we can plug that in to determine our dominant a little frequency and that is going to look like this. So solving for p P equals one minus Q. Therefore one minus 0.5 P also occurs at 0.5. A little frequency. But remember the question asks for the number of homo zegas dominant individuals. Therefore we need to figure out what P squared is, so P squared is going to equal 0.5 squared equals 0.25. If you multiply that by 100 That is going to give you 25%. So 25 of 25% of the population is home Ozekis, dominant. And the total number of the population is 8000, so 8000 times 0.25 is going to equal 2000, so 2000 of the individuals are homo Zegas dominant. Therefore the correct answer is B-2000. Alright, everyone, I hope you found this helpful and I'll see you soon for the next practice problem.