If 12 grams of helium and 20 grams of oxygen are placed inside a 5 liter cylinder at 30�C, what is the partial pressure of the helium gas? All right, so they're giving us information on 2 gases. They're giving us information on helium and oxygen, but realize they're only asking for information in terms of partial pressure for the helium.
With the helium I have it's grams and from that I can determine its moles. I have the volume of the container and I have the temperature of the container. With this information, I can find a partial pressure of helium gas by utilizing the ideal gas law. So we're going to say here pressure of helium equals moles of helium times R * T / V. We don't even need to look at the grants of oxygen because the question again is only asking about the partial pressure of helium.
All right, so let's take the 12 grams of helium. We look on the periodic table. You'll see that the atomic mass of helium is approximately 4.003g helium for everyone. More of helium grams here cancel out, and I'll have my moles as 2.9978 moles of helium. So take that. Plug it into the formula, so 2.9978 moles of helium multiplied by my gas law or my gas constant .08206 liters times atmospheres over moles times K.
Temperature must be in Kelvin, so the 30�C I'm going to add 273.5 to it and that gives me 303.15 Kelvin. Then we take the volume which is 5 liters and we just plug it in. Look at the units. Leaders cancel out with liters, Kelvin's cancel out with Kelvin's moles cancel out with moles. And at the end what we have left is atmospheres. So we plug that in and we'll get 14.9149 atmospheres.
If we look at the sig figs within our question, we have three sig figs, 3 sig figs, 2 sig figs, and one sig fig here. If we wanted one sig fig, it would round down to 10 atmospheres. Again, that's such a big deviation from our actual number. So let's go with a number that makes more sense because we don't want around so much. We're going to say our answer here is 14.9 atmospheres.
Again, we're constantly trying to remember significant figures play a role in a lot of our questions here. We're not being asked to directly, but when applicable we should alley it here. It wouldn't make sense to apply it because it would round our answer to a number that doesn't quite fit. Going from 14.9 to 10 is such a big difference. So here we're just going to go with three sig figs. 14.9 atmospheres is more reasonable.
It's not a big deviation from our original answer, so just remember if we have the moles, the temperature and the volume, we can find the partial pressure of a gas by using the ideal gas law formula.