So here it says determine systematic name of the following alkane. Our job is first to find the longest carbon chain which represents our parent chain. We're utilizing steps one to six. Remember, we're utilizing the rules that we learn in terms of naming out canes with substituents. You have to watch those videos, make sure you go back and take a look at those six steps.
So here 123-456-7899 seems to be the longest chain that we can have in terms of this alkane. So that is our parent chain. So we'll highlight it for ourselves. Now remember, we numbered from the end closest to a substituent. Here we have a three carbon substituent, A1 carbon substituent and bromine 1234. To get to this three carbon substituent or 123. To get to the bromine substituent, we numbered from the end closest to a substituent, so we're going to number it from the right side.
O 123456789 9 carbons mean that our alkane is no name. Now our substituents 3 carbon substituent with the bond on the middle carbon means that this is isopropyl. One carbon substituent would be methyl and then bromine is bromo. Remember we basically name we number these for their location and we write them alphabetically. B comes before I, I comes before M.
So we start out with three dash bromo, Dash isopropyl is on 6/6 isopropyl and then methyl is on 5/5 methyl. No name. So this would be the name of this particular alkane compound. Here we have the introduction of our halogen bromine group, which is listed as bromo.