In this reaction, we're going to talk about the halogenation reactions here. Under this type of reaction, 2 halogens coming from either BR2 or CL2 are added to one Pi bond. So here we have our starting alkene and we're reacting it with X2. In the process, each double bonded carbon gains 1 halogen. At the end of this we have a structure that has two halogens on it, which we call a dye halid.
Now if we have an alkyne, that means we have 2 π bonds. So remember we need one mole of reagent for every π bond, and since there's 2 π bonds here, we'd need 2 moles of X2. So the first mole would add to give us two halogens, and then the second mole would add again to give us another two halogens. At the end, you have a structure that possesses 4 halogens on it, so we'd call this a tetrahalid.
So remember, halogenation. Halogenation is just adding two halogens per π bond within your structure. This could give us a dye halid if you're dealing with an alkene, or a tetrahalid if you're dealing with an alkyne.