In this video we're going to take a look at alcohol reactions and in particular reduction reactions. So here we're going to say the reducing agent of sodium borohydride, which is NABH4 dissolved in water, reacts with an alcohol. Now reducing agent. This is just a compound used to reduce aldehydes and ketones. Now the carbonyl oxygen gains an H in this process and the carbonyl carbon also gains in HO. We're creating carbon hydrogen bonds.
Now if we take a look here, we're looking at reduction, so we're moving from left to right. Notice that we're ignoring the carbon dioxide, this carbonic acid and this hydrocarbon when it comes to reduction, at least in Gen. chem. When you get to organic, it's going to expand even more. But for right now, all you need to worry about is when we're talking about reduction, we're talking about aldehydes or ketones being reduced into some type of alcohol.
And like we said, we're adding an H to the carbonyl carbon and an H to the carbonyl oxygen. So if I'm adding an H to this carbon, I have to get rid of one of these π bonds because carbon can't make 5 bonds. Oxygen is ideal, number of bonds is 2, so it's lost a π bond of carbon. So to make up for that it also gains an H.
OK, so that's basically what reduction will be. Locate the carbonyl carbon, add an H to the carbon, add an H to the oxygen, and basically take away their π bond. In that way, you're going to transform an aldehyde or ketone into some type of alcohol.