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Ch 34: Geometric Optics
Chapter 34, Problem 34

A concave mirror has a radius of curvature of 34.0 cm. (b) If the mirror is immersed in water (refractive index 1.33), what is its focal length?

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1
Identify the formula for the focal length of a mirror in air, which is given by \( f = \frac{R}{2} \), where \( R \) is the radius of curvature.
Calculate the focal length in air using the given radius of curvature, \( R = 34.0 \, \text{cm} \).
Understand that when the mirror is immersed in water, the focal length changes due to the refractive index of the medium. The new focal length \( f' \) can be calculated using the formula \( f' = \frac{f}{n} \), where \( n \) is the refractive index of the medium (water in this case).
Substitute the refractive index of water, \( n = 1.33 \), and the focal length in air calculated in step 2 into the formula from step 3.
Calculate the new focal length \( f' \) of the mirror when it is immersed in water.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Focal Length of a Mirror

The focal length (f) of a concave mirror is related to its radius of curvature (R) by the formula f = R/2. This relationship indicates that the focal point, where parallel rays converge, is located at half the distance of the radius of curvature from the mirror's surface.
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Refraction and Refractive Index

The refractive index (n) of a medium indicates how much light slows down when it enters that medium. In this case, the mirror is immersed in water, which affects the effective focal length due to the change in the speed of light, requiring adjustments in calculations to account for the medium's refractive properties.
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Mirror Formula

The mirror formula relates the object distance (u), image distance (v), and focal length (f) of a mirror: 1/f = 1/v + 1/u. This formula is essential for understanding how the position of the object affects the image formed by the mirror, especially when considering changes in the surrounding medium.
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Related Practice
Textbook Question
The focal length of the eyepiece of a certain microscope is 18.0 mm. The focal length of the objective is 8.00 mm. The distance between objective and eyepiece is 19.7 cm. The final formed by the eyepiece is at infinity. Treat all lenses as thin. (b) What is the magnitude of the linear magnification produced by the objective?
330
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Textbook Question
Resolution of a Microscope. The formed by a microscope objective with a focal length of 5.00 mm is 160 mm from its second focal point. The eyepiece has a focal length of 26.0 mm. (a) What is the angular magnification of the microscope?
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Textbook Question
A telescope is constructed from two lenses with focal lengths of 95.0 cm and 15.0 cm, the 95.0-cm lens being used as the objective. Both the object being viewed and the final are at infinity. (b) Find the height of the formed by the objective of a building 60.0 m tall, 3.00 km away.
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Textbook Question
BIO (a) Where is the near point of an eye for which a contact lens with a power of +2.75 diopters is prescribed?
362
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Textbook Question
BIO Ordinary Glasses. Ordinary glasses are worn in front of the eye and usually 2.0 cm in front of the eyeball. Suppose that the person in Exercise 34.52 prefers ordinary glasses to contact lenses. What focal length lenses are needed to correct his vision, and what is their power in diopters?
380
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Textbook Question
BIO A person can see clearly up close but cannot focus on objects beyond 75.0 cm. She opts for contact lenses to correct her vision. (a) Is she nearsighted or farsighted?
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