Water is flowing in a pipe with a varying cross-sectional area, and at all points the water completely fills the pipe. At point 1 the cross-sectional area of the pipe is 0.070 m^2, and the magnitude of the fluid velocity is 3.50 m/s. (c) Calculate the volume of water discharged from the open end of the pipe in 1.00 hour.

Video transcript

Hey everyone. So this problem is dealing with volumetric flow rates. Let's see what it gives us a section of the pipeline has a cross sectional area of 1.15 square meters. And the velocity magnitude at that point is 1.8 m per second, determine the volume delivered to a tank every hour at the pipeline's terminal. So the volume delivered every hour is a is a rate. So it's asking us to find the volumetric flow rate. So the givens from the problem, we know area is 1.15 square meters and our velocity is 1.8 m per second. And we need to recall our continuity equation Q. That's our volumetric flow rate equals A B. So it, it really is that simple. It's a plug-in chug from there. So we have 0.15 m squared, that's 1.8 m per second. And that gives us 2.07 m cubed per second. They asked us for a rate in hours. So all we have to do is a little bit of unit conversion here, 2.07 m cube per second and then there's 3600 seconds in one hour. And that gives us 7452 m cubed per hour if you look at our choices, uh and the closest one is d they just rounded it to three significant figures instead of four. And so that is our answer, 7450 m cubed per hour. That's all for this one. We'll see you guys in the next video.