Atomic masses of elements can be found by simply looking at the periodic table. So let's start off by looking at the symbol of H, which represents hydrogen. And if you take a look at hydrogen as well as the other elements on the periodic table, you'll see these whole numbers. These whole numbers represent our atomic number. They are the number of protons. When we say atomic mass though, the atomic mass is the number that is seldom a whole number. This is our atomic mass. So you can find the atomic mass of any element on the periodic table just by simply looking it up. Now we're going to say the atomic mass itself is an average of all its isotopes that use the units of grams per mole, AMU, or Daltons, and we're going to say remember that 1 AMU equals 1.66 × 10 - 27 kilograms. So just remember, these atomic masses that you see on the periodic table, they are usually not whole numbers. You'd have to get way down below here to these heavy elements down here till you see whole numbers for atomic masses. And remember, they are the average of all the isotopes for that given element.
Atomic Mass (Simplified) - Online Tutor, Practice Problems & Exam Prep
The atomic mass of an element can be found on the Periodic Table.
Determining Atomic Mass
Atomic Mass (Conceptual) Concept 1
Video transcript
Atomic Mass (Conceptual) Example 1
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So here for this example question, it says, which of the following represents an element from the first column with the greatest atomic mass? Alright. So our first column, if we look at this periodic table, includes all of these different elements. And remember, the number in red, which is not a whole number normally, that represents the atomic mass of any of these given elements. Now here, if we take a look, we have barium, Ba. Again, later we'll learn about how the names are attached to the element symbol. Ba is not in the 1st column; here it's in the 2nd column. So this cannot be a choice. Then we're going to say next that we have Al. Al stands for aluminum. Aluminum is over here in the 3rd column, well, all the way over here in this 13th column, actually. So, this is out. Next, we have Cs, which is cesium. Here it is right here. It's in the first column. It's pretty low down there. It's 132.91 for its atomic mass. Remember, that could be in grams per mole, atomic mass units, or Daltons. So far, it looks like it's the highest one. The only one higher than that would be Fr. Notice that in the bottom rows here, most of them are whole numbers. These are super large mass elements that are pretty unstable. They typically don't have numerous isotopes. As a result, they have no decimal places. So, so far C looks like it's our best choice. If we look at D, we have Li, which is up here, not higher in mass, not greater in atomic mass. And then we have Na, which is right here. So it looks like C is our best choice. It has the greatest mass, atomic mass, from column 1 from the choices provided. So just remember we have our element symbols, we have our atomic masses, which normally are not whole numbers, and then we actually have whole numbers. Those represent our atomic numbers.
On the Periodic Table, the atomic mass is represented by the number with decimal places.
Which of the following choices has the greatest atomic mass?
Atomic Mass (Simplified) Concept 2
Video transcript
Now the atomic mass of an element can be calculated if you know the isotopic masses and percent abundances. Isotopic masses are the masses for all the isotopes of a given element. And percent abundance, sometimes referred to as natural abundances, are the percentages available for each of the isotopes of a given element. Sometimes they're referred to as percent natural abundances. I know it's a little bit redundant, but just remember, you might see percent abundances, natural abundances, or percent natural abundances.
Isotopic abundance, also called fractional abundance, is the percent abundance of an isotope divided by 100. Remember, when you divide a percentage by 100, you're changing it from its percentage form to its fractional or decimal form. All of this together gives us our atomic mass formula.
The atomic mass formula, we are going to say, equals the isotopic mass of isotope 1 times its isotopic abundance plus the isotopic mass of isotope 2 times its isotopic abundance. Of course, if you have more than 2 isotopes for a given element, this would just continue. You would keep adding, let's say, plus isotope mass 3 times its isotopic abundance plus isotope mass 4 times its isotopic abundance. In this example, we're just showing that this particular element we're talking about has 2 isotopes involved with it, and they both have their own masses. But again, this formula can be expanded to even more isotopes depending on the element. Elements such as manganese have various isotopes, so their formulas would be a lot larger.
In MathML format, the atomic mass formula can be presented as follows:
Atomic Mass = ∑in m i f iWhere mi is the isotopic mass and fi is the fractional abundance of isotope i.
Atomic Mass (Simplified) Example 2
Video transcript
In the following example question, it says, calculate the atomic mass of gallium if gallium has 2 naturally occurring isotopes with the following masses and natural abundances. So here we're dealing with gallium-69 and gallium-71. Their atomic masses are written in terms of atomic mass units, and then here we have 60.11% and 39.89%. Those represent the percent abundances. Now, to find the atomic mass of our gallium element, let's follow step 1. Step 1 says if you are given percent abundances, which we were, we're going to divide them by 100 in order to isolate our fractional abundances. So divide them both by a 100, when we do that we're going to get our fractional abundances.
Step 2, plug your given variables into the atomic mass formula in order to isolate the missing variable. So this is just a simple plug and chug algebraic type of situation. Our atomic mass of our element equals the mass of the first isotope times its fractional abundance plus the mass of our second isotope times its fractional abundance. So when we do that, we're going to get:
x = ( 69.7230 0.6011 + 71.0 0.3989 ) amuSince our isotopic masses have 4 decimal places, we could follow 4 decimal places here, but we have multiple choice options and we're going to go with the best answer, which would be option a for this particular question. So using the atomic mass formula is pretty simple. All we have to do is round up all the variables that you are given and isolate the one that's missing. From there, you can find your final answer.
Only three isotopes of magnesium exist on earth. 24Mg is the most common form at 78.70% natural abundance with a mass of 23.98504 amu, 25Mg has a 10.13% natural abundance, while 26Mg has a natural abundance of 11.17% and a mass of 25.98259 amu. What is the mass of the 25Mg isotope?
Silver has an atomic mass of 107.868 amu. The Ag-109 isotope (108.905 amu) is 48.16%. What is the amu of the other isotope?