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Ch.14 - Solutions

Chapter 14, Problem 62b

Describe how to prepare each solution from the dry solute and the solvent. b. 125 g of 0.100 m NaNO3

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Hi everyone. So as to describe the preparation of 100 16 g of 0.2 morality of sodium sulfate stri solute and solvent. Recall that morality is in malls they saw you. What about kilograms of the solvent? 0.2 malls. What about one kg And in one kg Have 1000 g and one more. I'm sorry. I'm so fake. The mother mass. MS 22 .990 g. That's 32 066 grams plus four. I was 15 .999 grams. Just to give us 119 g. I get 0.02 38 g. And I have grams of the solution. two g upsetting himself fate plus grams. H 20. Programs of the solution minus grams of sodium sulfate. Give us grams of H 0.02 38 g of sodium sulfate in one g Of H 20. And it's eager to eggs. Programs of study and soft bait About 1 16 g minus X. I'm scram. I'm setting myself fake X. Times. Graham's upsetting yourself. Faith Equals 0.02 38 g. Setting yourself faith five About 1 g H 20. I was 1 16 grams minus X. Times grams. Study yourself. Faith. X. Times grams. A sodium sulfate. Welcome to 2. 0.02 38 X. Times grams of sodium sulfate X. Times grams of sodium sulfate 0.02 38 times X times grams upsetting soft bait. 2.6 0. oh eight At 1.02 times X times grams of sodium soft bait To 2.76 oh eight. So you divide both sides 1.02 x. Times grams of sodium sulfate. It was 2.696 six. Get g of H 20. Instagrams of the solution minus grams of sodium sulfate, The g of H 20. There's 116 g -2.6966 grams. The programs are H 20. At 1 13. So we're gonna dissolve 2.70 grams of setting himself bait In 113 grams of distilled water. Thanks for watching my video. And I hope what's up for.
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Describe how to prepare each solution from the dry solute and the solvent. c. 125 g of 1.0% NaNO3 solution by mass

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