Skip to main content
Ch.14 - Solutions

Chapter 14, Problem 56

A dioxin-contaminated water source contains 0.085% dioxin by mass. How much dioxin is present in 2.5 L of this water? Assume a density of 1.00 g>mL.

Verified Solution
Video duration:
2m
This video solution was recommended by our tutors as helpful for the problem above.
2095
views
3
rank
Was this helpful?

Video transcript

Hey everyone today, we're being asked to find the mass of toxin present in a 3. liter water sample that has 0.025% toxin by mass. So to do this, the very first thing we can do is convert our volume, Our 3.4 L in two ml. And this is because the density given for this solution is in g per milliliter. This will help us with our calculations. So 3.4 L of water Can be converted to ml by remembering that we have 1000 ml for every one liter of water. So our leaders will cancel out and we will be left with 3400 ml of water from here. Taking this value. R 30 400 ml can then be multiplied by the density 1.01 g per one millimeter. In order to yield us A math of 34, 34 g of water. So now, since we know that this value is 0.025% toxin by mass, then that means we can take this mass 3434 g and that can be multiplied by the percentage 0.025 toxin For every 100 g of the sample of the water. So our grams will cancel out and simplifying this And solving it were left to the value of 0. 85 grams of toxin. Therefore there are Or there is 0.8585 g of toxin In a 3.4 liter water sample. I hope this helps, and I look forward to seeing you on the next one.