Name each amine b.

Video transcript

welcome back everyone in this example, we need to identify the pack name of the following aiming. So what we should recall is that our Aipac rules tells us to find the longest continuous arrangement of carbon in our structure. And so recall that in our structure each corner represents a carbon atom. So we would have a carbon here, a carbon here, a carbon here, we have a carbon here. Carbon here and a carbon here. And versus counting a count of 12 or in this case one, sorry 12, we would have a count of 123 which is a continuous count of carbons on this chain, on the right hand side. And so this would be our longest carbon chain in the structure, meaning we should also recognize that it's bonded next to this. NH recall that this is our aiming group. So and a mean is our type of group in an organic molecule where we have nitrogen bonded according to its bonding preference to three atoms with its one lone pair. Where one of these bonds to an atom can be a hydrogen atom and then the other two can be our group. So we would have our one and then our two in this case meaning we would have a secondary aiming. So the degree of our aiming corresponds to how many are groups. It's bonded to meaning we have to our groups. So we have a secondary aiming and right now we counted a continuous chain of carbon atoms in a three carbon chain here. So we label them as one, sorry, 12 and three. And as we stated this is our continuous carbon chain where we named this carbon carbon one because it's closest to our aiming group which is considered high priority. We also want to recognize that are aiming group is our root modifier of our name but we want to figure out what our route is. Before we focus on our route modifier which is just the name of the group being aiming. And so our root name is going to be based on what we counted out of our continuous carbon chain which was three carbons in a chain where we recognize that these three carbons are all bonded in sigma bonds. So single bonds which we recall tells us that we have an L. Kane chain So we have a three carbon will say well kaine chain this is going to correspond to the route where corresponding to three carbons we have prop and then we know it's an al cane. So we'll end it by saying aim. Now we want to focus on adding in our root modifier. So we're going to get rid of that suffix E. And we're going to replace it with our route modifier. So we would have pro open naming as our new root modified name. So we have proper name. I mean just so that's clear. So now that we have our route modifier and root combined. Now let's focus on any substitute prints attached to our group being are aiming here and we can see that what we have coming off from this nitrogen is a carbon atom bonded to two other carbon atoms. Where these two other carbon atoms are bonded to a total of three hydrogen. Is because we want to call that carbons bonding preference to be stable is to have four bonds. So these hydrogen are going to be implied. What we should recognize this entire group here as is as a substitute known as an isopropyl. So let's go ahead and highlight this isopropyl as our substitute. Now we want to recall that we designate substitue ints by their location and in this case our substitution isopropyl is not bonded to a carbon atom. So we're not going to be using a number two designated location. Instead we see that it's bonded to our nitrogen atom in our gaming group meaning its location is defined by that nitrogen. And so we would say that its location is going to be N. Isopropyl. And now that we have our location of the substitue ints in our structure as well as our root modifier. We're going to combine the two to get our name. So we would say substitue into plus root modifier equals our name of our structure and what we will have is as a whole M I. So appropriate all and then we're going to have our route modifier. Pro pa naming now recognize that we have this hyphen between N and isopropyl because N. Is designating its location, it being the substitution isopropyl. And so we want to designate the location separate from the name of our substitution, which is why we have this hyphen. So I hope that that's clear. This entire name is our final answer as the pack name of our structure given in the prompt. I hope everything I reviewed was clear. If you have any questions, leave them down below and I will see everyone in the next practice video.