Draw the structure of each aldehyde or ketone. a. hexanal

Video transcript

Welcome back everyone. What is the structure of Beet and L and aldehyde? Let's recall for this problem that aldehydes have a general form of an alkyl group bonded to car bono that has hydrogen directly attached to it. So that's the general form of an aldehyde. And whenever we want to draw a structure of an aldehyde, we of course, want to essentially begin with the car bono group, add hydrogen and then think about the number of carbon atoms within the alky group. Let's recall that carbon number one always corresponds to the carbon of Carboni. And now, according to the name, our parent is Benel itself, which corresponds to Bane when we think about L canes. And we know that Bane is a four member chain. Now, it's really important to understand that the total number of carbon atoms in the longest continuous carbon chain for beats now would be four, meaning carbon number one already belongs to our longest continuous chain. So we have three carbons remaining to draw, we have carbon number one, followed by carbon number two, number three and number four, let's count them 1234. Well, then we have the structure of beats. Now, let's go ahead and label it as our final answer and thank you for watching.