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Ch.16 - Aqueous Equilibria: Acids & Bases

Chapter 16, Problem 5

What is the concentration of hydroxide ions 3OH-4 in a glass of wine with pH = 3.64? (LO 16.5, 16.6) (a) 2.3 * 10-4 M (b) 6.4 * 10-3 M (c) 6.8 * 10-9 M (d) 4.4 * 10-11 M

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Hello everyone today. We are the following problem, calculate the concentration of hydroxide ions of a sample of vinegar with the ph of 2.75. So the first thing that we want to highlight here is the following equation and that is that the ph plus the P. O. H. Those two values are going to equal 14. So knowing that we have the value of our ph we can rearrange this equation to solve for the P. O. H. And that would be 14 minus R. P. H. Which is 2.75. And we result with a p. h. of 11.25. And we're gonna hang on to that number. We have the P. O. H. We can solve for the concentration of hydroxide ions. And why is that? Well the concentration of hydroxide ions is actually equal to 10 raised to the negative P. O. H. And so if we plug in our values we have 10 race to the negative 11.25 And that is going to come out to a value of 5.6 times to the negative 12th as our final answer. And so with that we have answered our question overall. I hope that this helped and until next time