Consider the conjugate bases, 1X-, Y-, Z-2 in Problem 2. If you mix equal concentrations of reactants and products, which of the following reactions will proceed to the left? (LO 16.3) (a) HX + Y- HY + X- (b) HX + Z- HZ + X- (c) HY + X- HX + Y- (d) HZ + Y- HY + Z-

Question

Molecular representations of HX, HY, and HZ in acid-base equilibrium.

Accepted Answer

Hello. In this problem we are shown 0.1 molar solutions of H X. H Y N H C. Brass. To assume that equal concentrations of the acids are mixed and we want to know which of the reactions below favors the reactant. Let's begin by looking at the images we've been provided. We have then in each case we have the un dissociated acid. We have the conjugate base of that acid and we have hydrogen mines. So taking into account all those different particles that are shown beginning with H. X. We have three and associated molecules. We have three high the mines which came from three hydro lines and we have three of our conjugate base. For H. Y. We have to And associated as molecules we have four adjoining mines came from the 400 lines and we have four of our conjugate base. And then for H. C. We have one and associate as molecule we have five hydrogen mines and we have five of our contacted base. So looking at these three different assets. Then the one that associates the most is the strongest. So that would be Hc and the one that associates the least will be our weakest. So writing these in order of increasing acid strength and H. C. Is the strongest by H. Y. And then H. X. Is the weakest recall. Then the stronger the acid, the weaker its conjugate base. So Z minus would be the weakest base followed by y minus and then X minus to be the strongest base. Looking at the reactions that we've been provided the first one we have H. C. On the reacting side and we have a checks on the product side. So H C. Is a stronger acid than H. X. Which means it's going to drive this reaction in the forward direction. We look at the next one, we again have a checks now on the reacting side and H. C. On the product side, Hz being a stronger asset, is going to drive this reaction in the first direction. The next one we have H. C. On the reactive side and H. Y. On the product side. So H C. Being a stronger acid is going to drive this reaction in the forward direction and the last one we have H. Y. And H X. So H Y is a stronger acid than H H X. So it will drive the reaction in the forward direction. So the one reaction that we have that is going in the reverse direction towards reactant is B. So this is then the reaction that favors the reactant. Thanks for watching. Hope this helped

Consider the conjugate bases, 1X-, Y-, Z-2 in Problem 2. If you mix equal concentrations of reactants and products, which of the following reactions will proceed to the left? (LO 16.3) (a) HX + Y- HY + X- (b) HX + Z- HZ + X- (c) HY + X- HX + Y- (d) HZ + Y- HY + Z-

Verified Solution

Key Concepts

Conjugate Acid-Base Pairs

Le Chatelier's Principle

Equilibrium Constant (K)