Provide a formula for tri Aqua dibromo, carbonyl manganese 3 chloride. Alright, so first we need to identify the cation and the anion. That's the easy part because remember when it comes to naming the whole entire coordination compound, there's a space that separates our cation name from the anion name. So this first part would have to be our cation because cation was written first and so the chloride would have to be our anion.
Next we list formulas of metals, ligands and the counter ion. So here let's look at this. We have, let's see, manganese 3. Remember the transition metals written first? So manganese 3 is Mn3⁺. Then we have tri Aqua. Aqua is water and there's three of them, so put it in parentheses. Let's see. Next we have Dibromo. So that's two bromines. Alright, there's two of them. And then we have carbonyl which is CO and let's see chlorite is ClO2⁻.
Next, that prewrite formula of the complex ion and identify its charge. Right, transition metal before the ligands, right? Neutral ligands before anionic ligands, both in alphabetical order. So let's just do that first. Alright. So what do we have? We have Manganese 3⁺ and let's see, we write this alphabetical order. Let's see. So we're going to say here we have, let's see, Aqua is neutral, then we have bromide ion and then we have our carbonyl.
So the neutral ones are Aqua and carbonyl. Remember the neutral ones come first, so A before C. So Aqua is written first, so H2O (3). Then we're going to write CO and then Bromo. Even though B comes before C, it's anionic in nature, so it can't be written before carbonyl. So we write Br here, and there's two of them. It's a complex ion, so we're going to place it in brackets, and we need the charge of it, alright?
So we just have to add up everything. We have 3⁺ from the manganese. Water is neutral, carbonyl is neutral, so they don't contribute to the overall charge, so we can ignore them. We have two bromide ions, each one is -1, so this becomes 3⁺ - 2. So the overall charge of this complex ion is 1⁺. Now that we have the complex ion, we move to step four. We add the counter ion to the outside of the bracket of the complex ion. So you're going to write cation before anion and then you balance charges.
Alright, so this is our cation. So it's written first. Chloride is our anion, so it's written second. The numbers in the charges are the same, so when they combine, they just cancel out. The formula for this coordination compound would be manganese with the three waters, the carbonyl, the two bromides, and then ClO2. This would be our final answer.
