Provide the systematic name for the following carbacillic acid here. To do that, we're going to utilize these steps in terms of naming the molecule before us. O Here's step one. Find the longest carbon chain. This will represent our parent chain and assign name according to the prefixes and modifier. The parent change should include the carbosilic acid group and greater number of carbons. Now if a tie between longest chain, choose chain with more substituents.
All right, so we're going to find the longest carbon chain we got to make sure that the carbon silic acid group is part of it. So if we look, this would be the longest carbon chain. So we can go this way, or you can go this way. Both would give us the same length for the carbon chain and the same number of substituents. So here I'm just going to go by the original way. This way.
Now assign name to all the substituents for Step 2. So here we have a bromine group as a substituent, so this will be bromo. And then here we have a three carbon alkyl group, which is ethyl. Start numbering the chain at the carbon of the carbasilic acid group, so COOH group. So this would be 12345 and six, and then steps four to six. We repeat steps from previous naming topics. Mainly, we give numerical locations to the substituents, we make sure that they're named alphabetically in a relation to each other, and we make sure we use commas to separate numbers and dashes or hyphens to separate letters from numbers.
O here alphabetically B comes before E though bromo is on carbon 3, so 3 bromo and then we have the ethylene carbon 4/4 ethyl. Since the carbosillic acid carbonyl carbon is carbon number one, we don't have to give it a number of designation. So we have a six carbon chain which is hexane. But we changed the E ending to hexanoic acid, here it becomes OIC acid. So the name of our carbosolic acid here will be 3 bromo 4 ethyl hexanoic acid.