After glucose is fully oxidized by glycolysis, pyruvate processing, and the citric acid cycle, where is most of its energy stored?

Video transcript

Hi everyone. Let's look at our next question. It says the product of the complete oxidation of glucose after the Krebs cycle that has the highest amount of energy is. And our choices are a T P N A D H F A D H two and acetyl coa A. I'm gonna go ahead and eliminate choice D. Acetyl coa a. That's not the product of the complete oxidation of glucose. Acetyl coa A. Is the at the beginning of the Krebs cycle. That compound that enters the Krebs cycle. So we're just going to rule that out right now. So our remaining three choices all our have high amounts of energy. Um But any D. H and F A T H two can be used to produce a T P. So we can eliminate a TP as well because N A. D. H and F A T H two in their roles, electron carriers will both generate multiple molecules of a teepee, therefore having more energy. And finally between these two, f a t H two enters the electron transport chain. It brings its electrons further down the electron chain. So when it carries its electrons, each molecule of F A T H two only generates 2 80 p molecules while N A T H, which deposits its electrons at the beginning of electron transport chain, each molecule will generate 3 80 p molecules. So therefore we can eliminate choice C. And stated choice B N A D H has the highest amount of energy because each molecule of N A. D. H can be used to produce three molecules of a teepee by oxidative phosphor relation. See you in the next video.