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Ch 03: Motion in Two or Three Dimensions
Chapter 3, Problem 3

At its Ames Research Center, NASA uses its large '20-G' centrifuge to test the effects of very large accelerations ('hypergravity') on test pilots and astronauts. In this device, an arm 8.84 m long rotates about one end in a horizontal plane, and an astronaut is strapped in at the other end. Suppose that he is aligned along the centrifuge's arm with his head at the outermost end. The maximum sustained acceleration to which humans are subjected in this device is typically 12.5g. (b) What is the difference between the acceleration of his head and feet if the astronaut is 2.00 m tall?

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1
Identify the radius of rotation for both the head and the feet of the astronaut. The radius for the head is the length of the centrifuge arm, 8.84 m. The feet are 2.00 m closer to the rotation axis, so the radius for the feet is 8.84 m - 2.00 m = 6.84 m.
Use the formula for centripetal acceleration, which is given by \(a = \frac{v^2}{r}\), where \(v\) is the tangential velocity and \(r\) is the radius of rotation. Since \(v\) is the same for both the head and the feet, the difference in acceleration will depend on the difference in the radii.
Calculate the angular velocity (\(\omega\)) of the centrifuge using the maximum acceleration experienced by the head. The formula relating centripetal acceleration and angular velocity is \(a = \omega^2 \times r\). Solve for \(\omega\) using the head's radius and maximum acceleration.
Compute the centripetal acceleration for the feet using the angular velocity found in the previous step and the radius of the feet. Use the formula \(a = \omega^2 \times r\).
Find the difference in acceleration between the head and the feet by subtracting the acceleration of the feet from the acceleration of the head.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Centripetal Acceleration

Centripetal acceleration is the acceleration experienced by an object moving in a circular path, directed towards the center of the circle. It is calculated using the formula a_c = v^2/r, where v is the tangential velocity and r is the radius of the circular path. In the context of the centrifuge, the astronaut experiences varying centripetal acceleration at different points along the arm due to the rotation.
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Gravitational Acceleration (g)

Gravitational acceleration, denoted as 'g', is the acceleration due to Earth's gravity, approximately 9.81 m/s². In the context of the centrifuge, the term '12.5g' indicates that the astronaut experiences an acceleration 12.5 times that of gravity, or about 122.625 m/s². This hypergravity condition affects the astronaut's body differently at various heights, leading to a difference in acceleration between the head and feet.
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Height and Acceleration Difference

The difference in acceleration between the astronaut's head and feet arises from their vertical separation in the centrifuge. Since the head is farther from the axis of rotation than the feet, it experiences a greater centripetal acceleration. This difference can be calculated by considering the height of the astronaut and the radius of rotation, illustrating how rotational motion affects different parts of a body in a non-uniform manner.
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Related Practice
Textbook Question
A 124-kg balloon carrying a 22-kg basket is descending with a constant downward velocity of 20.0 m/s. A 1.0-kg stone is thrown from the basket with an initial velocity of 15.0 m/s perpendicular to the path of the descending balloon, as measured relative to a person at rest in the basket. That person sees the stone hit the ground 5.00 s after it was thrown. Assume that the balloon continues its downward descent with the same constant speed of 20.0 m/s. (a) How high is the balloon when the rock is thrown?
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Textbook Question
A 124-kg balloon carrying a 22-kg basket is descending with a constant downward velocity of 20.0 m/s. A 1.0-kg stone is thrown from the basket with an initial velocity of 15.0 m/s perpendicular to the path of the descending balloon, as measured relative to a person at rest in the basket. That person sees the stone hit the ground 5.00 s after it was thrown. Assume that the balloon continues its downward descent with the same constant speed of 20.0 m/s. (c) At the instant the rock hits the ground, how far is it from the basket?
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