Skip to main content
Ch 03: Motion in Two or Three Dimensions

Chapter 3, Problem 3

Two piers, A and B, are located on a river; B is 1500 m downstream from A (Fig. E3.32). Two friends must make round trips from pier A to pier B and return. One rows a boat at a constant speed of 4.00 km/h relative to the water; the other walks on the shore at a constant speed of 4.00 km/h. The velocity of the river is 2.80 km/h in the direction from A to B. How much time does it take each person to make the round trip?

Verified Solution
Video duration:
7m
This video solution was recommended by our tutors as helpful for the problem above.
1946
views
Was this helpful?

Video transcript

Hi, everyone. Let's get started. So two residences, ion residences located upstream and Omega residences located downstream are located along the river sign as showed The distance between the two residences is 1800 m. Diego and Paul must make round trips between the two residences starting from ion residences. Paul is paddling a canoe at a constant speed of 4.50 km/h hour relative to the water in the river. On the other hand, Diego walks on the riverside at a constant speed of 3.7 km/h. The velocity of the stream in the river is 2.60 km/h in the direction from ion to Omega. So it's the river is traveling from left to right. As you can see here, how long will it take for Paul and Diego to make the round trip? So what do we know? We are given a distance De of 1800 m And since we're making a round trip, we're gonna multiply that by two. So our total distance that our friends need to travel is 600 m. Now we're given their speeds in kilometers per hour. So we're going to have to do some converting. Mhm. So Paul's speed on on the river is going to be 4.50 km/h. And Diego's speed walking alongside the river is going to be 3.7 km/h. So first thing I wanna do is convert our distance into kilometers and we're going to use a conversion factor to do that. So one kilometer is equivalent to 1000 m. So are 3600 m should be 3.6 kilometers now because we know that our speed is our distance over time, we can speed equals distance over time. Of course. So we can substitute our values here. I'm gonna start with our friend Diego since he's just walking along the side of the river that makes it a little easier. Yeah. So Diego is moving at 3.7 km/h And he wants to walk 3.6 km. That's gonna be our distance. And our time is what we don't know. That's what we're trying to find. So if we rearrange this equation and solve it, we can conclude that time is approximately 58.4 minutes. That's how long it's going to take Diego to walk to and from the, the residences. So let's see if we can check our answer choices here and cross out any that don't agree with ours. So we can see that our time for Diego and each answer is different in each one. And actually a is the only one that lines up with our value. So answer a time for Diego to travel equals 58.4 minutes And time for Paul to travel equals 72.1 minutes. Must be the correct answer. Thank you.
Related Practice
Textbook Question
At its Ames Research Center, NASA uses its large '20-G' centrifuge to test the effects of very large accelerations ('hypergravity') on test pilots and astronauts. In this device, an arm 8.84 m long rotates about one end in a horizontal plane, and an astronaut is strapped in at the other end. Suppose that he is aligned along the centrifuge's arm with his head at the outermost end. The maximum sustained acceleration to which humans are subjected in this device is typically 12.5g. (b) What is the difference between the acceleration of his head and feet if the astronaut is 2.00 m tall?
2609
views
2
rank
1
comments
Textbook Question
The coordinates of a bird flying in the xy-plane are given by x(t) = αt and y(t) = 3.0 m − βt2, where α = 2.4 m/s and β = 1.2 m/s2. (a) Sketch the path of the bird between t = 0 and t = 2.0 s.
598
views
Textbook Question
The nose of an ultralight plane is pointed due south, and its airspeed indicator shows 35 m/s. The plane is in a 10–m/s wind blowing toward the southwest relative to the earth. (a) In a vector-addition diagram, show the relationship of υ→ P/E (the velocity of the plane relative to the earth) to the two given vectors.
924
views
Textbook Question
A railroad flatcar is traveling to the right at a speed of 13.0 m/s relative to an observer standing on the ground. Someone is riding a motor scooter on the flatcar (Fig. E3.30). What is the velocity (magnitude and direction) of the scooter relative to the flatcar if the scooter's velocity relative to the observer on the ground is (a) 18.0 m/s to the right?

1053
views
Textbook Question
A daring 510-N swimmer dives off a cliff with a running horizontal leap, as shown in Fig. E3.10. What must her minimum speed be just as she leaves the top of the cliff so that she will miss the ledge at the bottom, which is 1.75 m wide and 9.00 m below the top of the cliff?

4707
views
Textbook Question
A man stands on the roof of a 15.0-m-tall building and throws a rock with a speed of 30.0 m/s at an angle of 33.0° above the horizontal. Ignore air resistance. Calculate (d) Draw x-t, y-t, υx–t, and υy–t graphs for the motion.
1172
views