An astronaut has left the International Space Station to test a new space scooter. Her partner measures the following velocity changes, each taking place in a 10-s interval. What are the magnitude, the algebraic sign, and the direction of the average acceleration in each interval? Assume that the positive direction is to the right. (a) At the beginning of the interval, the astronaut is moving toward the right along the x-axis at 15.0 m/s, and at the end of the interval she is moving toward the right at 5.0 m/s. (b) At the beginning she is moving toward the left at 5.0 m/s, and at the end she is moving toward the left at 15.0 m/s. (c) At the beginning she is moving toward the right at 15.0 m/s, and at the end she is moving toward the left at 15.0 m/s.

Video transcript

Hello. So ride oh is testing its new product which is a minute for that is designed for kids. The test aims to study the changes in the velocities of the mini car at five second intervals. What is the average celebration? Each of the following intervals? Consider the convention that the East direction is positive. So in the first interval many car is moving 1.5 m per second to the east and at the end it is moving to the east at 1.2 m per second. At the start of the second interval, the mini car is moving due west at 1.75 m per second and the at the end it is moving to still third interval minicar is moving to the east and 1.9 m per second. And at the end it is moving to the west at 1.9 m per second. So we call since we're looking for acceleration that the average acceleration is equal to delta V or delta T, which is equal to me, F minus V. I for the delta T two. And in this case all the intervals are delta T. Is equal to five seconds five seconds and were given that the east direction is positive. So anything moving west Use less than zero. Anything moving east spring. So using this we can now solve for the average acceleration in all these cases he's one A and C. Books, you be with the T. F. Is east at 1.2 m per cent. So we have that two m per second positive. And at the initial point it is moving 1.5 years of seconds, so -1.5 per second over the time. Which is equal to - .06 m/s second. With trouble acceleration is also equal to delta V, delta T. You know, and at the end It is moving two m/s. West In this case dot their views negative two m/s. If you have the minus the initial velocity is west at 1.75 - negative. I'm doing some art peters for a second. All over the five cities. Yeah, The average acceleration is negative 0. third interval acceleration. That is moving west and 1.9 m/s and minus Velocity initially, which is east 1.9 m Verse seven. So it's positive 197 Over the 5 2nd time equal to zero, It was for seven. So using these values, first one is negative 0.6. 2nd one is negative 0.5. The third one is zero. So we know that the answer choices. C Okay, cells have a winter