14 g of nitrogen gas at STP are pressurized in an isochoric process to a pressure of 20 atm. What are

(a) the final temperature,

Question

14 g of nitrogen gas at STP are pressurized in an isochoric process to a pressure of 20 atm. What are

(a) the final temperature,

Accepted Answer

Hi, everyone. In this practice problem, we're being asked to compute the final temperature of a 22 g sample of gaseous oxygen at 25 degrees Celsius undergoing an increase in pressure from one ATM to 16 ATM at constant volume. The options given for the final temperatures are a 4770 Kelvin B 4500. Kelvin C 298 Kelvin and D 550. Kelvin, we will take the Gaius oxygen to be an ideal gas. So let's write that down here, ideal gas as our first assumption and we are told that the gaseous oxygen changes pressure at constant volume. So it will undergo an iso process. So in this case, after um simplifying the ideal gas law, we will obtain the equation of TF divided by T I equals to BF divided by P I for an iso cons uh iso constant volume process. So in this case, what we are interested to find is the final temperature or TF which we can rearrange our previous equation that we obtained from the Ideal Gas Law simplification to then be equal to PF divided by P I multiplied by T I. We are given all of the information in the problem statement to calculate our final temperature from this formula right here. So let's substitute all of our values. So TF will be equal to PF or the final pressure which is going to be 16 ATM divided by the initial pressure or P I which is one ATM multiplied by the initial temperature T I which is going to be 25 degrees Celsius, which we have to convert into Kelvin. So T I is 25 degrees Celsius and converting that into Kelvin, we will have, we will have 25 plus 273 Kelvin. So that will be 298 Kelvin. So TF will be equals to 16 ATM divided by one A PM multiplied by 298 Kelvin just like. So calculating this, we will get our final temperature to then be equal to 4768 Kelvin, which will be able to be rounded up to be 4770 Kelvin. So the final temperature from this process for the gaseous oxygen is going to be 4770 Kelvin, which will correspond to option A in our answer choices. So option A will be the answer to this particular practice problem and that'll be it for this video. If you guys still have any sort of confusion, please feel free to check out our other lesson videos on similar topics available on our website. But other than that, that'll be it for this video. And thank you so much for watching.

14 g of nitrogen gas at STP are pressurized in an isochoric process to a pressure of 20 atm. What are (a) the final temperature,

Verified Solution

Key Concepts

Ideal Gas Law

Isochoric Process

Standard Temperature and Pressure (STP)