10:24Electric Field (2 of 3) Calculating the Magnitude and Direction of the Electric FieldStep by Step Science355views
Multiple ChoiceA 1.5μC charge, with a mass of 50g, is in the presence of an electric field that perfectly balances its gravity. What magnitude does the electric field need to be, and in what direction does it need to point?1059views23rank5commentsHas a video solution.
Multiple ChoiceIf two equal charges are separated by some distance, they form an electric dipole. Find the electric field at the center of an electric dipole, given by the point P in the following figure, formed by a 1C and a −1C charge separated by 1 cm.1251views18rank9commentsHas a video solution.
Multiple Choice4 charges are arranged as shown in the following figure. Find the magnitude of the electric field at the center of the arrangement, indicated by the point P.1544views21rank12commentsHas a video solution.
Multiple ChoiceIn the following figure, a mass m is balanced such that its tether is perfectly horizontal. If the mass is m and the angle of the electric field is θ, what is the magnitude of the electric field, E, expressed in terms of m, q, and θ?682views12rank2commentsHas a video solution.
Multiple ChoiceA 1.2g plastic bead is given a charge of −14 nC by rubbing. What magnitude and direction of electric field is necessary to levitate the bead?246views
Textbook QuestionTwo positive point charges q are placed on the x-axis, one at x = a and one at x = -a. (a) Find the magnitude and direction of the electric field at x = 0.887viewsHas a video solution.
Textbook QuestionA +8.75-mC point charge is glued down on a horizontal frictionless table. It is tied to a -6.50-mC point charge by a light, nonconducting 2.50-cm wire. A uniform electric field of magnitude 1.85 * 10^8 N/C is directed parallel to the wire, as shown in Fig. E21.34. (b) What would the tension be if both charges were negative?854viewsHas a video solution.
Textbook QuestionA +8.75-mC point charge is glued down on a horizontal frictionless table. It is tied to a -6.50-mC point charge by a light, nonconducting 2.50-cm wire. A uniform electric field of magnitude 1.85 * 10^8 N/C is directed parallel to the wire, as shown in Fig. E21.34. (a) Find the tension in the wire.258viewsHas a video solution.
Textbook QuestionCP A proton is traveling horizontally to the right at 4.50 * 10^6 m/s. (c) What minimum field (magnitude and direction) would be needed to stop an electron under the conditions of part (a)?216viewsHas a video solution.
Textbook QuestionCP A proton is traveling horizontally to the right at 4.50 * 10^6 m/s. (b) How much time does it take the proton to stop after entering the field?304viewsHas a video solution.
Textbook QuestionCP A proton is traveling horizontally to the right at 4.50 * 10^6 m/s. (a) Find the magnitude and direction of the weakest electric field that can bring the proton uniformly to rest over a distance of 3.20 cm.1476views7rankHas a video solution.
Textbook QuestionA very long, straight wire has charge per unit length 3.20 * 10^-10 C/m. At what distance from the wire is the electricfield magnitude equal to 2.50 N/C?1236viewsHas a video solution.
Textbook QuestionA point charge is placed at each corner of a square with side length a. All charges have magnitude q. Two of the charges are positive and two are negative (Fig. E21.42). What is the direction of the net electric field at the center of the square due to the four charges, and what is its magnitude in terms of q and a?94viewsHas a video solution.
Textbook Questiona. Starting from rest, how long does it take an electron to move 1.0 cm in a steady electric field of magnitude 100 N/C?311viewsHas a video solution.
Textbook QuestionA 10.0 nC charge is located at position (x, y)=(1.0 cm, 2.0 cm). At what (x, y) position(s) is the electric field c. (21,600 î−28,800ĵ) N/C?181viewsHas a video solution.
Textbook QuestionA small 1.0 g block charged to 75 nC is placed on a 30° inclined plane. The coefficients of static and kinetic friction are 0.20 and 0.10, respectively. What minimum strength horizontal electric field is needed to keep the block from sliding down the plane?226views1rankHas a video solution.
Textbook QuestionAn electric field E=200,000î N/C causes the point charge in FIGURE P22.68 to hang at an angle. What is θ?357views1rankHas a video solution.
Textbook QuestionA 0.10 g honeybee acquires a charge of +23 pC while flying. b. What electric field (strength and direction) would allow the bee to hang suspended in the air?80viewsHas a video solution.
Textbook QuestionA −12 nC charge is located at (x, y)=(1.0 cm, 0 cm). What are the electric fields at the positions (x, y)=(5.0 cm, 0 cm), (−5.0 cm, 0 cm), and (0 cm, 5.0 cm)? Write each electric field vector in component form.123viewsHas a video solution.
Textbook QuestionINT A proton is fired horizontally into a 1.0×10^5 N/C vertical electric field. It rises 1.0 cm vertically after having traveled 5.0 cm horizontally. What was the proton's initial speed?275views1rankHas a video solution.
Textbook QuestionA −15 nC charge is at x=+2.0 cm on the x-axis. A second charge q is located somewhere on the x-axis to the left of the origin. The electric field at y=2.0 cm on the y-axis is Ē =3.0×105 î N/C . What are (a) the charge q in nC and (b) its distance from the origin?18viewsHas a video solution.
Textbook QuestionA thin, horizontal, 10-cm-diameter copper plate is charged to 3.5 nC. If the charge is uniformly distributed on the surface, what are the strength and direction of the electric field (a) 0.1 mm above the center of the top surface of the plate?17viewsHas a video solution.
Textbook QuestionFigure 24.32b showed a conducting box inside a parallel-plate capacitor. The electric field inside the box is E (→ above E) = 0 (→ above 0) . Suppose the surface charge on the exterior of the box could be frozen. Draw a picture of the electric field inside the box after the box, with its frozen charge, is removed from the capacitor. Hint: Superposition.159viewsHas a video solution.
Textbook QuestionThe three parallel planes of charge shown in FIGURE P24.44 have surface charge densities ─ ½ η , η , and ─ ½ η. Find the electric fields EA (→ above E) to ED (→ above E) in regions A to D. The upward direction is the + y-direction.247viewsHas a video solution.
Textbook QuestionA 0.80-μm-diameter oil droplet is observed between two parallel electrodes spaced 11 mm apart. The droplet hangs motionless if the upper electrode is 20 V more positive than the lower electrode. The density of the oil is 885 kg/m³ . (c) Does the droplet have a surplus or a deficit of electrons? How many?171viewsHas a video solution.
Textbook QuestionCALC Charge Q is uniformly distributed along a thin, flexible rod of length L. The rod is then bent into the semicircle shown in FIGURE P23.48. a. Find an expression for the electric field Ē at the center of the semicircle. Hint: A small piece of arc length Δs spans a small angle Δθ=Δs/R , where R is the radius.10viewsHas a video solution.