33. Geometric Optics
Mirror Equation
33. Geometric Optics
Mirror Equation
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- Multiple Choice
A 4 cm tall object is placed in 15 cm front of a concave mirror with a focal length of 5 cm. Where is the image produced? Is this image real or virtual? Is it upright or inverted? What is the height of the image?
1187views4comments - Multiple Choice
You want to produce a mirror that can produce an upright image that would be twice as tall as the object when placed 5 cm in front of it. What shape should this mirror be? What radius of curvature should the mirror have?
681views2rank4comments - Multiple ChoiceAn object is in front of a converging lens with a focal length of . Use ray tracing to determine the location of the image. Is the image upright or inverted?331views
- Multiple Choice
A 4 cm tall object is placed 15 cm in front of a concave mirror with a focal length of 5 cm. Where is the image produced? Is this image real or virtual? Is it upright or inverted? What is the height of the image?
366views6rank - Textbook QuestionA concave mirror has a radius of curvature of 34.0 cm. (b) If the mirror is immersed in water (refractive index 1.33), what is its focal length?534views
- Textbook QuestionThe thin glass shell shown in Fig. E34.15 has a spherical shape with a radius of curvature of 12.0 cm, and both of its surfaces can act as mirrors. A seed 3.30 mm high is placed 15.0 cm from the center of the mirror along the optic axis, as shown in the figure. (a) Calculate the location and height of the of this seed.565views
- Textbook QuestionDental Mirror. A dentist uses a curved mirror to view teeth on the upper side of the mouth. Suppose she wants an erect with a magnification of 2.00 when the mirror is 1.25 cm from a tooth. (Treat this problem as though the object and lie along a straight line.) (b) What must be the focal length and radius of curvature of this mirror?575views
- Textbook QuestionA spherical, concave shaving mirror has a radius of curvature of 32.0 cm. (b) Where is the ? Is the real or virtual?491views