A short RNA molecule was isolated that demonstrated a hyperchromic shift (see Chapter 10), indicating secondary structure. Its sequence was determined to be

     5'-AGGCGCCGACUCUACU-3'

What DNA sequence would give rise to this RNA molecule through transcription?

Video transcript

Hi everyone. Let's take a look at this practice problem together. The anti code on loop of the blank that carries a sequence of three nucleotides is complementary to the code on present on the blank. Now, you should recall and know what code on an antique odin are. So let's review those. A code on is present on M R N A and it is three nucleotides long. It encodes for an amino acid. So the second fill in the blank is M R N A. Now an anti code on is the complementary part to the code on. It is found on T R N A. It is also three nucleotides long. It does not encode for amino acids but it is an adapter molecule and it brings the amino acid to the ribosomes during translation. So T R N A will be the first fill in the blank. So the correct answer therefore is option C T E R N A M R N A. Now to review how they interact if you have a M RNA sequence with C C C. So this is our M R N A, this is our code on and then you would have a corresponding complementary sequence on the anti code on loop of the T RNA molecule. So G G G and this together with the ribosome allowed protein or polyp peptide sequence. Also just to mention a review, this M I R N A, these are small non coding RNA S, they're involved in gene expression regulation and not involved in translation. So an anti cotton loop of the T R N A that carries the sequence of three nucleotides is complementary to the code in present on the M RNA. So option C is the correct answer. Alright, everyone. I hope you found this helpful and I'll see you soon for the next practice problem.