Base-substitution mutations often change the amino acid ...

Question

Base-substitution mutations often change the amino acid specified by a codon. For each of the amino acid changes listed, determine which ones can result from a one–base-pair substitution. For those that can result from a one–base-pair substitution, give the possible wild-type and mutant codons, listing multiple possibilities if there is more than one option. (Use either Figure 9.13 or the genetic code in Table A to help solve this problem).

Wild-type Mutant
a. Ser Ala
b. Cys Ser
c. Pro Glu
d. Lys Stop
e. Met His
f. Met Ile

Accepted Answer

Hey, everyone. Let's take a look at this question together a mutation that changes the code on A U G to C U G would result in the incorporation of which amino acid is it? Answer choice. A methionine instead of lucine. Answer choice B lucine instead of methionine, answer choice C prolene instead of methionine or answer choice D isoleucine instead of methionine. Let's work this problem out together to try to figure out which of the following amino acids would be incorporated as a result of this mutation. So we have two codons, we have a U G and we have C U G and we can see from our codon table that the codon A U G is the start codon which we know codes for methionine, which means that the mutation causes a replacement of that amino acid methionine. So answer choice A can be eliminated. Since in answer choice, a methionine is replacing leucine and it is that amino acid methionine that is being replaced. And we can see in our codon table that the codon C U G codes for the amino acid leucine. So this mutation that changes the codon from A U G to C U G results in the change of lucine instead of methionine. So that means that answer choice B is the correct answer. Since the other answer, choice mutation changes are incorrect. And answer choice B is the correct mutation change of lucine replacing methionine. I hope you found this video to be helpful. Thank you and goodbye.

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