Write balanced complete ionic and net ionic equations for each acid–base reaction. a. HBr(aq) + NaOH(aq) → b. HF(aq) + NaOH(aq) → c. HC₂H₃O₂(aq) + RbOH(aq) →

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Hello. Everyone in this video, we want to find out what is the balance Complete ionic equation for this base reaction of these two key players here are also being asked what is its net ionic equation. So an acid based reaction is a reaction between an acid and a base which results in a production of salt. So this first reaction here that's a weak acid and L. I. O. H. This is a group one, a hydroxide assault, which means that we have a strong base, so weak acid and strong base. So from a chemical reaction, let's write this out. We have C. Six H. Five C. O. H. This is a quiz and this reacts with L. I. O. H. Which is also a quiz. And this will yield a product of L. I. C six H five C O. Which is a quiz as well as H 20. Which is a liquid. So let's first balance this chemical reaction. I'd like to put a line to separate our reactions and our products by key players here of course the C H O N. L. I simply for the other side. See H. O. And L. I. So based on here from my carbon we have seven Hye Jin's, we have three oxygen. We have three and lithium. We have one from products that we have 77, three and 1. So if we put a coefficient I made a little steak here actually are hygienic on my starting material side is actually seven. So we just take a look then everything here is actually balanced. So that's going to be our balanced chemical reaction. We all need to add any coefficient. So using that then we can go ahead and determine the complete ionic equation. So soluble ionic compounds will separate and become ions in the chemical reaction compounds are a quiz. Can bring it up into ions and insoluble compounds regarding solids, liquids and gasses will not break up in the solution. So our complete ionic equation then is going to be C six H. Five C. 00 minus. They're acting with H Plus reacting with L. I. Plus as well as O. H minus. This will go ahead to yield L. I. Plus C. six H 5 c. O minus and H. 20. Liquid. Alright so that's our first part of the answer. This again the complete ionic equation. So using that we can go ahead and find the net ionic equation. So we just need to remove spectator ions and this species president both the on the product side and the productive side. So taking a look at the ionic equation, you can see here that we can cut out this here right here as well as our lithium plus carry on since it presents itself on both sides. Then our net ionic equation is going to be a church plus a quiz reacting with H minus which is a quiz. And this will give us a church to O. And its liquid state. So this is my last and final answer for this problem.

Write balanced complete ionic and net ionic equations for each acid–base reaction. a. HBr(aq) + NaOH(aq) → b. HF(aq) + NaOH(aq) → c. HC2H3O2(aq) + RbOH(aq) →

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Write balanced complete ionic and net ionic equations for each acid–base reaction. a. HBr(aq) + NaOH(aq) → b. HF(aq) + NaOH(aq) → c. HC₂H₃O₂(aq) + RbOH(aq) →