Write structural formulas for each of the nine structural isomers of heptane.

Video transcript

everyone in this video we're being asked to give five different structural I. Summers for the molecule Hixon. So first of all identify the heck scene has six carbons. So that's c. six and then we have H. 14. So this is what it is. And let's also recall that what I saw remember even means so customers are compounds with the same number of atoms but different arrangements of atoms in the molecule. So basically all the atoms are arranged differently. But this formula here stays the same. So no matter how we structure this molecule we're still gonna have six carbons and 14 hydrogen. Alright so we can go ahead and get started on the first one and kind of manipulate the one that we just drew originally. So the first one we can do like you said there's six carbons so we can have a chain. So we have CH three at the left siege two CH two CH two. So that's 1234. We have four carbons, we continue our chain. And then when we reach our last carbon of course that's is a method of CH three. So again we have 123. Let's see 123456. That is six carbons. So that's one of our first structures. The 2nd 1. Then let's go ahead and add a branch or a sort of like a substitute. Print we can add a substitute print on any of the chains. We'll just do it for the second-carbon right here. So again we have our H. Three C. Now instead of a C. H. Two because we want to add a branch of Ch three, this will just have one hydrogen And then we'll continue a chain of CH two. Let's see here now we have 12345, so one more carbon. So now we have a CH three at the end. Alright, so that's our second third. What we can do is like I said, we're kind of just manipulating each one so now that we have a method here we can go ahead and add another one maybe right over here just do the third carbon on our parent chain. So again starting off with our terminal carbon H three C. And then we have the second carbon with a CH three group. Then we said for this one we'll also add a CH three. So again this will have just one hydrogen and their chain is C H three in their last and final carbon will be C H three of course. Alright, again, that's 123456 carbons. Now our fourth we're going to do for our fourth ice mur is maybe have a metal On our 3rd carbon. So we're starting off with our again H three C. Then we have a central carbon CH two and then another C. So for the third carbon I said I want to add a ch three group, so there it is, so the central carbon will not have one hydrogen continua chain again. So CH two and their terminal C H three. Alright, so that's our fourth Eisenberg. Let's do for our 5th Eisenberg, a more interesting shape. We can do sort of a TERT boodle substitue intent. So we can have a carbon with three methyl groups. So CH three, CH three, Ch 3. Okay, so we have used four carbons, so now you can add another one right here and then another terminal one here. Alright, so you see 123456. So that's six carbons. Alright then. These are all five of our different structural members for molecule C six H 14, also known as heck Scene.