Based on the molecular formula, determine whether each compound is an alkane, alkene, or alkyne. (Assume that the hydrocarbons are noncyclical and there is no more than one multiple bond.) a. C5H12 b. C3H6 c. C7H12 d. C11H22

Video transcript

Hey everyone, we're asked to classify each of the following compounds as an al caine. Al keen or alkaline, assuming that only one multiple bond is present and all are non cyclical first. Let's go ahead and define each of our options and write out our formulas for an L. Kane. We have an N amount of carbons and a two N plus two amount of hydrogen for an al keen. We have an amount of carbons and to an amount of hydrogen. And lastly for an alkaline, we have an amount of carbons and two n -2 for hydrogen first. Let's go ahead and look at a we have C nine H 16. We know that our end is going to be nine. So we can multiply nine times two to get 18 And we can see that in order to get 16, we had to subtract two. Looking at our formulas, we know that this is going to be an AL kind since we have C N H two N -2 as our formula structure. Next looking at B, we have C four H eight. Again, we're going to say N is going to be four and we're going to multiply this by two and we end up with eight. So that means we have an AL king Since we have that structure of CNH- two n. Next looking at C, we have C eight H 16 And will be eight and we can multiply eight times two and we end up with 16. So this means that C is also going to be an al keen Due to that formula structure of CNH- two n. Lastly looking at D, we have C six H 14 and will be six. Multiplying six times two, we get 12. And in order to get 14 hydrogen we have to add to Which gets us to 14. So this means that we have an al caine, since we have that structure of C n H two N plus two. So these are going to be our final answers. So I hope that made sense and let us know if you have any questions.