Which hybridization scheme allows the formation of at least one p bond? sp3, sp2, sp3d2

Video transcript

hey everyone in this example, we need to identify the hybridization that can form two pi bonds. We should recall that we form pi bonds from the overlap of RP orbital's. So we would have to pee orbital's that would overlap and their overlap would appear by the following diagram. We also want to recall that within the p sub level we have three orbital's which can hold a maximum of six electrons. So looking at our first example in a were given the hybridization sp We would recognize that here, we only have one p orbital. And so we would say that therefore we would have two P orbital's left for pi bonds. So we would go ahead and confirm choice A as a correct choice Where we would have to pee orbital's left over to overlap to form two pi bonds. Now moving on to example, B we have an sp three hybridization for adam And within sp three hybridization We see that we use three p orbital's. And so because we've used all three of our p orbital's, we would say that therefore there are zero P orbital's to make pi bonds. So we would rule out B as a hybridization for an atom to form two pi bonds. So in our last example we're given a hybridization for an atom of sp three D. And here we see that we would use three p orbital's and so therefore we would also have an atom with zero P orbital's for pi bonds. So we would rule out C. As well leaving a as the only example of a hybridization for an atom where we would have to pee orbital's available to overlap to form two pi bonds. So is our final answer to complete this example. If you have any questions, please leave them down below, and I will see everyone in the next practice video.