The concentration of a solution of potassium permanganate, KMnO4, can be determined by titration with a known amount of oxalic acid, H2C2O4, according to the following equation:
What is the concentration of a KMnO4 solution if 22.35 mL reacts with 0.5170 g of oxalic acid? (LO 4.22)
(a) 0.6423 M
(b) 0.1028 M
(c) 0.4161 M
(d) 0.2569 M

Question

The concentration of a solution of potassium permanganate, KMnO4, can be determined by titration with a known amount of oxalic acid, H2C2O4, according to the following equation: 
What is the concentration of a KMnO4 solution if 22.35 mL reacts with 0.5170 g of oxalic acid? (LO 4.22) 
(a) 0.6423 M
(b) 0.1028 M
(c) 0.4161 M 
(d) 0.2569 M

Accepted Answer

Hello everyone today we got the following problem. The concentration of hydroquinone solution was measured by thai tradition with a known quantity of Siri um For sulfate, the overall reaction is as follows. And we have this chemical reaction here, Calculate the concentration of the hydrocortisone solution given that 18. ml of the solution reacted with 3.065 g of Syrian sulfate. So the first thing you must do is you must balance his equation. And so the first you want to look at is are their equal amounts of atoms or elements on both sides on the left. We have six carbons and six carbons on the right are hydrogen. We have six on the left, six on the right for our Siri. Ums we have only one on the left but two on the right. So we have to add a two in front of the serie um That needs that additional one. And so now we see that we have four sulfates on the left and four on the right. And we have now balanced our equation. So now that we have balanced the equation, we need to take into account our molar mass of Siri um four sulfate. And so the formula for that is going to be using the molar mass, the 1 40.116 g per one mole of cesium of Siri um sulfate. And actually adding that two, The amount of moles that we have. So for our 32.066 g promote. This is going to stem from our amounts of oxygen or our amounts of sulfur. And then for our oxygen's we'll have 16 g per one mole times eight. And this will give us 332 point 248 grams per mole. So we'll stay, we'll store that number for later. Next we need to find the number of moles of our hydro Cranham. We can do so by using the mass given to us our 3. g and multiplying that by the molar mass of Syrian sulfate that we just solved for which is one mole of Siri um sulfate equaling 332. g of Siri um sulfate. And then lastly, of course, we need to go from moles of syria sulfate, two moles of hydroquinone. So we can use the ratio that for every one mole of hydroquinone, We have two moles of Siri um sulfate. And we got those numbers from the numbers in front of our reactant and our products. So that coefficient becomes how much of that we have. And so we saw for this, we see that we have four times 6125 times 10 to the negative third moles. As for our last step we need to find the polarity of this hydroquinone or the concentration of hydroquinone. So we need to do a series of steps first, we need to take the moles of hydroquinone that we sold for our 4.6125 times 10 to the negative three moles of our hydroquinone and divide that by how much leaders that we have, which is 18.45 mL. And to find leaders, we simply take this 18.5 mL and multiplied by the conversion factor that one middle leaders equal to 10 to the negative third leaders. And when units cancel that, we end up with 0.1845 liters. So they plug that in 0.1845 liters. And then we saw for concentration, we get .2500 Mueller as our final answer. And with that we've answered the question overall, I hope this helped until next time.

Verified Solution

Key Concepts

Titration

Stoichiometry

Molarity