What is the systematic name for each of the following ions? 

(c) [Co(CO₃)₃]^3-

(d) [Pt(en)₂(SCN)₂]²⁺

Video transcript

All right. Hi, everyone. So for this question, let's give the correct systematic name or the one N ID me two, no 222 positive ion and the part two irox 33 negative ion. Here we have four different answer choices, proposing different names for both ions. So based off what's given here, right, both ions are considered complex ions and recall that complex ions are composed of one metal cion forming the center of the complex as well as molecules or ions connected to the metal center referred to as ligands. So starting off with the first ion that's N I DME two oops, no 22 too positive. I generally prefer to start by naming all ligands in alphabetical order. So we'll go ahead and do that just now, right? In this case, it looks like we have two different types of ligands, one abbreviated as DME and the other being no two. Now recall that the no two ligand actually has a negative charge because these are night show groups, these are my short legs. So for the nitro ligand recall that it happens to be mono dentate, meaning that there is only one point of attachment of the ligand to the central metal. So the prefix necessary to indicate its quantity depends on whether it is mono dentate or poly dentate. So in this case, it's mono dentate and there are two nitro ligands which means that the name becomes di nitro. Now, the second one here abbreviated as DME stands for Die Metox Ate. Now recall that the di the dimeth boxy ethane is a poly dentate ligand and it already has a prefixed dye within the name. So this means that the prefix necessary to indicate its quantity is going to be slightly different, right? Because we have two dimeth oxy ethane ligands, the prefix becomes Biss and the name dimeth oxy Ethane is enclosed in parentheses immediately after this prefix. So now that all ligands have been listed, we have to go ahead and name our central metal. Now, our central metal in this case happens to be an I or nickel. Now because the overall complex ion has a positive charge, the name of the metal is not actually going to change. However, because it is a transition metal, there has to be a Roman numeral in parentheses after the metal's name to specify its oxidation state. So to find the oxidation state, recall that the charge of the complex is the total oxidation number of the complex and also the sum of the oxidation states of the metal and all ligands present must equal the total oxidation number of the complex. So if the oxidation state of nickel is X, then the sum of X and the oxidation states of both ligands also taking into consideration their quantity must equal the overall charge of positive two. Now recall the dimeth oxy ethane is neutral, meaning that its oxidation state is zero. Whereas the nitro ligands having a charge of negative one have an oxidation state of negative one. So in my equation, right, because the oxidation state of dimeth oxy Ethane is zero. Its term in my equation here cancels out and then I have two nitro ligands each with an oxidation state of negative one. So my equation simplifies to X subtracted by two equals positive two. So when I add both sides by two, I get that X is equal to positive four, that corresponds to the oxidation state of my central metal, which means that after the name nickel should be a Roman numeral four. So when I combine everything, I'm first going to go ahead and name my ligands in alphabetical order depending on their name and not their prefix, right. So because the D in dimeth oxy Ethane goes before the N in Nitro, my name becomes bis Dimeth Oxy Ethane D Nitro nickel four. And now we can proceed to the next part or the next ion, right? So for part two, we have Ir ox three three negative. So once again, I want to go ahead and start with my legs and it just so happens that I only have one type of ligand of which there are three, right? Because I have three ligands abbreviated as ox. Now recall that ox is shorthand for the oxalate ion. However, the obsolete ion has a charge of negative two, meaning that it is an anionic ligand. This means that the suffix of the ion's name gets dropped and replaced with an O right. So instead of saying oxalate, it becomes oxido or ox alao. And because the silat ligand is poly dentate, then the appropriate prefix for the quantity of three is tris as opposed to try. And the name oxo is enclosed in parentheses immediately after the prefix tris. So now the next step is to name the central metal. Now, ir indicates that the central metal is iridium. However, the name of the metal changes because the complex is anionic, it has an overall negative charge, right? The suffix I um in iridium gets dropped and replaced with a te. So instead of saying iridium, the name becomes irritate. So now there has to be a Roman numeral indicating the oxidation state, right. So X which is the oxidation state of iridium here added to three, multiplied by the oxidation states of the oxo lateral ligands should equal negative three which is the overall oxidation state. So, like I said previously, right, the olla ligand is anionic with a charge of negative two. This means that the oxidation state is going to be negative too. So when I multiply the oxidation state by the quantity of the ligand, I get that X subtracted by six equals negative three. So when I add both sides by six, I get that X is equal to positive three. So now I can go ahead and, and place a Roman numeral three after the name irritate. And so I put all of the information be gathered together to create the final name of truth Oxilan irritate three and there you have it. So if I scroll up here to see the answer choices, our answer is going to be option C in the multiple choice because the systematic name for ion one was bis dimeth oxy, ethane, di nitro nickel four and for ion two, it was tris oxy lateral iodate three. So if you stuck around to the end, thank you so very much for watching. And I hope you found this helpful.