Is the pH greater than, equal to, or less than 7 after the neutralization of each of the following pairs of acids and bases? (c) KOH and HI

Video transcript

Welcome back, everyone. We need to determine the ph after neutralization of the following acid base pair, lithium hydroxide and nitric acid. So let's begin by writing out our reaction between lithium hydroxide and sorry about that. L I O H and H N 03 nitric acid. So for lithium hydroxide recall that this is a strong base and nitric acid we want to recall is a strong acid. We should recognize that the reaction that they have with one another is going to be a double displacement reaction. And so because these are both strong acid or both strong species as far as being a base and an acid in the case of nitric acid recall that strong acids and strong base, it's completely dissociate in solution. And so we would have our reaction arrow where in our double displacement are lithium ion is going to react with our nitrate poly atomic, an ion and our hydroxide, an ion is going to react with our hydrogen cat ion or proton here, which is a part of nitric acid. And so we would form two products where we would have our lithium nitrate salt form. And then we have our second product which is water recognize that this double displacement reaction as the prompt states as a neutralization reaction. And in every neutralization reaction, our product is always going to be assault with water in solution. So we need to complete this reaction by writing in our labels. So we have to Aquarius reactant and our product, our salt is an Aquarius salt and water is a liquid, of course. So now with these labels, we need to write out our ionic equation in which we would just write out all of the ions involved in this reaction. So looking at lithium hydroxide, as we stated, we have our lithium plus one carry on, Then we have hydroxide which forms a -1 an ion. Then we have our proton apart of nitric acid H plus and then we have our nitrate poly atomic, an ion Which is a 1 -5. This completes the ions of our reactant. Now we have our reaction arrow and writing out the ions of our products. We have our lithium plus one caddy on our nitrate minus one, an ion and liquid water. Since it's not agree, it's, it's just a liquid here. So recall that from our ionic equation, we can go next into our net ionic equation because the difference between these two is that our net ionic equation cancels out all of our common species, meaning what we see on both sides of the reaction. And so canceling out our common species. We see we have lithium caddy on, on the reacting side, which we can cancel out with lithium caddy. On, on the product side, we can also cancel out our nitrate an ion on both sides of the reaction. And what we're left with will be our net ionic equation. And so what we have is our proton and our one mole of hydroxide, which forms our product water. And so ultimately, because we have water as our final product here, we can say that at neutralization of our acid and base, we have water which forms. So water is formed and recall that water has a ph equal to seven. And this makes sense because water has an equal number of hydrogen ions and hydroxide ions. And so our solution is balanced, ultimately explaining our ph of seven. So for our final answer, we have successfully identified our ph of our solution following the neutralization of our acid base pair, lithium hydroxide and nitric acid. Our final answer corresponds to choice be in the multiple choice. I hope that everything I reviewed was clear. If you have any questions, please leave them down below. And I'll see everyone in the next practice video.