The equilibrium constant Kn for the neutralization of lactic acid (C3H6O3) and urea (CH4N2O) is 2.1 x 10^-4. What is Kb for urea? The Ka of lactic acid is 1.4 x 10^-4.

Video transcript

Hello everyone today. We have the following question. The neutralization between acetic acid and nicotine has an equilibrium constant case of in of 1.8 times 10 to the third. What is the KB for the nicotine? If the K. A. For acetic acid is 1.8 times 10 to the negative fifth. Well the first thing I wanna do is you want to recall that this is a reaction between a weak acid which is acetic acid and a weak base which is nicotine. And so we also want to recall the formula for the equilibrium constant. K sub N is equal to. Okay. Times are KB divided by our K. W. And so if we rearrange this equation to find KB we will get that the KB is equal to our equilibrium constant times our K. W. Divided by our K. A. And we're gonna plug in these values. So R K. And r equilibrium constant value is 1.8 times 10 to the third and R K. W. And this is a constant. That can be found in reference text is of one times 10 to the negative 14th. We're going to divide that by RK. A. value which we were given for acetic acid which was 1.8 times 10 to the negative fifth. Doing so well us A K. B. Value of one times 10 to the negative six as our final answer. Overall I hope this helped. And until next time