Write balanced chemical equations to correspond to each of the following descriptions: (b) Boron sulfide, B2S31s2, reacts violently with water to form dissolved boric acid, H3BO3, and hydrogen sulfide gas.

Question

Accepted Answer

Hi everyone today, we have a question telling us that the reaction of solid iron sulfate and hydrogen gas produces solid iron and gasses hydrogen sulfide, Right? The balanced reaction equation. So first we need to figure out what our iron sulfide is going to look like. So we have iron With a plus three charge And we have sulfur with a -2 charge and we need to crisscross these and that gives us two iron and three sulfur. And now we need to do the same with our hydrogen sulfide. So we have hydrogen with a plus one charge, and we have sulfur with a -2 charge. And again we're going to criss cross these and that gives us two hydrogen and one sulfur. So now that we know what those look like, we can write out our equation. So we have our iron sulfide and it is a solid and we have our hydrogen gas and it's going to form our hydrogen sulfide, which is gaseous plus solid iron. Now we need to balance this. So let's write out our elements and how many we have of each. So we have to iron, three sulfur and two hydrogen. And on this side we have one iron, one sulfur and two hydrogen. So our first step is going to put a three here so that we'll have three sulfur And that changes us to six hydrogen. So now we're gonna go over here and put a three in front of this hydrogen to make this six and now all we have to fix is our iron. So we can put a two in front of our iron and that is fixed. So this is our final balanced equation. Thank you for watching. Bye.

Write balanced chemical equations to correspond to each of the following descriptions: (b) Boron sulfide, B2S31s2, reacts violently with water to form dissolved boric acid, H3BO3, and hydrogen sulfide gas.

Verified Solution

Key Concepts

Chemical Equations

Reactivity of Boron Compounds

Acid-Base Reactions