The figure that follows contains ball-and-stick drawings of three possible shapes of an AF4 molecule. (a) For each shape, give the electron-domain geometry on which the molecular geometry is based. ii.

Video transcript

Hello everyone today. We have the following problem. Consider the figure below of three possible shapes for an A. B. Three molecule identify the electron geometry for each. So for our first molecule here we notice we have one central atom. So we'll denote this with an A. As a central atom. And we have three atoms around it, these white spheres around it. And so we represent those white series with X. And then we have three of them. So three. When we have this configuration, this is known as a tribunal planer molecule. Not take care of our answer for the first molecule. For the second molecule we can note that this one is interesting because the geometry the shape of it is different. It seems to be a little bent so that would denote the presence of a lone pair on the central atom. And once again that central atom is going to be A. And for electron groups we have these three white spheres. And we also have this electronic group as a lone pair at the top here. And so therefore we have four electron groups. And when we have that set up, the electron geometry is going to be tetra he drew. And that will be our answer for the second molecule. For the third molecule. This one is an interesting shape as well. This one is actually T shaped and so in T shaped molecules we have five electron groups. And so each of these spheres represents if each of these surrounding serious represents one electron group, we must therefore add two lone pairs as these lone pairs are electron groups as well. And so as before our a. Is going to represent our central atom and then we're going to have X5. And this electron geometry is going to be known as tribunal by pira middle. And that will be our answer for the third and final molecule. And with that we have our complete answer. I hope this helped. And until next time.