Consider the Lewis structure for glycine, the simplest amino acid:

(b) What are the hybridizations of the orbitals on the two oxygens and the nitrogen atom, and what are the approximate bond angles at the nitrogen?

Video transcript

Welcome back everyone. We're told that the lewis structure, formulaic acid is given below how many sigma bonds and pi bonds are in the entire molecule. So first let's make note that in our molecule we have a total of six single bonds. An account of three double bonds. Recall that double bonds are represented as pi bonds and single bonds are represented as sigma bonds. So we can say that therefore we have six sigma bonds and therefore three pi bonds. Now, within our pi bonds, we want to recall that our pi bonds or our double bonds are made up of one pie Plus 1 σ Bond. And that means we can say we have three pi bonds plus three sigma bonds in whole. And so for our total sigma bonds, sorry, sigma bonds here, we would have six plus three, which gives us a total of nine sigma bonds. And then for our total pi bonds we would just have our three pi bonds. And so for our final answers, we've successfully determined the number of pi bonds and sigma bonds being three and nine that make up our structure of melodic acid. Our final answer corresponds to choice, be in the multiple choice as the correct answer. I hope this made sense. And let us know if you have any questions