The two most common isotopes of uranium are 235U and 238U. (d) 238U undergoes radioactive decay to 234Th. How many protons, electrons, and neutrons are gained or lost by the 238U atom during this process? (e) Examine the electron configuration for Th in Figure 6.31. Are you surprised by what you find? Explain.

Video transcript

everyone in this example. We have the atom Siri um 1 41. It's a radioactive isotope undergoing beta decay to form praise Od me. Um 1 41 the isotope and it's a isotope of the rare earth metal. Praise od me. Um We need to write the electron configuration for a President Me. Um 1 41 adam and determine whether there's anything surprising in its electron configuration. When we find presidium on our periodic tables, we would recognize it in the fourth energy level of our F block, which is our Land Tonight series and recalling that atomic number is represented by the symbol Z. We would see that it has an atomic number of 59. So to begin its configuration, we're going to find the Shorthand configuration where we'll take the noble gas in brackets that comes before atomic number 59. And looking at our noble gas group that would correspond to the noble gas Xenon. Starting out with our lowest energy level, We're going to recall that again. Praise or a medium is in the Land tonight series, which begins at the fourth energy level of our F block. And we would count for a total of three units in our Land Tonight series of R. F. Block to get to our atom praise od me. Um so we would fill in for three electrons. We should recognize that because President Diem has atomic number 59. We also need to fill in the atoms that occur at Atomic numbers 55 and 56 which begin at our six energy level of R. S. Sublevel and that covers the atom cesium and barium. So we're going to fully fill in this sub level to get to our atom praise od me um in our Land Tonight series for F block. And so what we have listed is going to be our configuration are shorthand configuration for our presidium 1 41 Adam. And we would determine that there is nothing surprising as our second answer based on the configuration. We've determined everything has worked out accordingly to our rules for configurations. And so this configuration is just a standard configuration. So this would complete our example as our final answers. If you have any questions, just leave them down below and I'll see everyone in the next practice video.